13 because an atom has the same number of protons as neutrons
Answer:
If the temperature of gas is decreased the pressure will also goes to decrease.
Explanation:
The pressure and temperature have direct relation. If the temperature of gas will increase the pressure of gas will also goes to increase.
According to the Gay-Lussas's Law,
The pressure of given amount of gas is directly proportional to the absolute temperature when volume is kept constant.
Mathematical relationship:
P ∝ T
P = kT
P/T = k
and
P₁/T₁ = P₂/T₂
Answer:
The sample of lithium occupies the largest volume.
Explanation:
Given the densities for the four elements, we have the expression
that shows the relationship between mass and Volume to express the density of an element.
For each element we have:




The problem says that all the samples have the same mass, so:

it means that m is a constant
Now, solving for the Volume in each element and with m as a constant, we have:












If we assume m = 1g, we find that:




So we can see that the sample of lithium occupies the largest volume with 1.88mL
Note that m only can take positive values, so if you change the value of m, always will be the lithium which occupies the largest volume.
<h2>Answer:</h2>
The<u> diffusion </u>occurs in room.
- <u>Oder molecules move from their highest concentration to lowest concentration.</u>
<h3>Explanation:</h3>
Diffusion is a process by which molecules move down their concentration gradient. The process does not require any membrane.
So corner with perfume has high concentration of odor molecules. Hence they move to other corner with low concentration of molecules.
Hello!
Reading the worksheet shows you how to find the concentration of liquid water in a substance, but when converting a decimal to a percentage, remember that ALL percentages are out of 100, so, we multiply the decimal by 100 to convert it into a percentage.
Liquid A: total amount: 10 millimeters & amount of water: 7 millimeters
7/10 = 0.7 × 100 = 70%
Liquid B: total amount: 100 millimeters & amount of water: 92 millimeters
92/100 = 0.92 × 100 = 92%
Liquid C: total amount: 15 millimeters & amount of water: 13 millimeters
13/15 = 0.867 × 100 = 86.7%
Liquid D: total amount: 28 millimeters & amount of water: 22 millimeters
22/28 = 0.786 × 100 = 78.6%
<u>Final answers</u>:
- Liquid A: 70%
- Liquid B: 92%
- Liquid C: 86.7%
- Liquid D: 78.6%