(a) at the bottom - high density organic compound dissolved in methylene chloride
(b) at the bottom - saturated aqueous sodium chloride
Explanation:
Sodium chloride is dissolved in water while the organic compounds are dissolved in methylene chloride. After mixing the two solutions two layers will form because water (polar molecule) will not mix with the methylene chloride (nonpolar molecule).
The layer with higher density will be at the bottom.
(a) saturated aqueous sodium chloride (d = 1.2 g/mL) - upper layer
high density organic compound dissolved in methylene chloride (d = 1.4 g/mL) - bottom layer
(b) saturated aqueous sodium chloride (d = 1.2 g/mL) - bottom layer
low density organic compound dissolved in methylene chloride (d = 1.1 g/mL) - upper layer
Learn more about:
liquids with different densities
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Depression in freezing point (Δ
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) =
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×m×i,
where,
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= cryoscopic constant =
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,
m= molality of solution = 0.0085 m
i = van't Hoff factor = 2 (For
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)
Thus, (Δ
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) = 1.86 X 0.0085 X 2 =
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Now, (Δ
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) =
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- T
Here, T = freezing point of solution
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= freezing point of solvent =
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Thus, T =
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- (Δ
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) = -
Answer:
your answer would be the last one gold
The reaction is:
Cl2 + 2 KBr --> 2 KCl + Br2
Moles of KCl is
n = m /M = 12 /74 = 0.16 mol
As, twice the moles of KCl is producing from 1 mol of chlorine
mole of Cl2 = 0.16 /2 = 0.08 mol
Mass of Cl2
m /70 = 0.08 = 5.6 g
Hence, 5.6 g mol Cl2 consumed to produce KCl
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