Well cutting off the small 4x2 you get 8 plus’s the 7x2 is 14 so just add those together you should get 22in ^2
Ok
y=-0.04x^2+8.3x+4.3
when the rocket reaches the ground (when height=0, ie when y=0), then the rocket will land, find the x coordinate
set y=0
0=-0.04x^2+8.3x+4.3
use quadratic formula
if you have ax^2+bx+c=0, then
x=

a=-0.04
b=8.3
c=4.3
x=

x=208.017 or -0.516785
xrepresents horizontal distance
you cannot have a negative horizontal distance unless you fired and theh wind blew it backwards
therefor x=280.017 is the answer
208.02 m
Answer:
(x - 1)² = 0
Step-by-step explanation:
Given
x² - 2x + 1 = 0 ( subtract 1 from both sides )
x² - 2x = - 1
To complete the square
add ( half the coefficient of the x- term )² to both sides
x² + 2(- 1)x + 1 = - 1 + 1
(x - 1)² = 0
Just multiply the 0.003 by 10 and you'll get the result. The easiest way to multiply such numbers is to move the dot one position to the right (it would be 2 positions if multiplied by 100, 3 by 1000 etc.). You can do the same with dividing, just remember to move to the left then.
So 0.03 is your answer
<span>Hope I Helped!!!</span>