3 years ago

State how many imaginary and real zeros the function has.

1 answer:

7 0

Hello,
Degre 5==> even number of imaginary roots and odd number of reals.

Real roots must be a divisor of 7.
Using Excel, we find

 x P(x)
-7 0 
 -6 1369
 -5 1352
 -4 867
 -3 400
 -2 125
 -1 24
0 7
1 32
2 225
3 1000
4 3179
5 8112
6 17797
7 35000

So: one real root: 7 and 4 imaginary roots.

Answer B

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