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2 years ago

State how many imaginary and real zeros the function has.

1 answer:

7 0

Hello,
Degre 5==> even number of imaginary roots and odd number of reals.

Real roots must be a divisor of 7.
Using Excel, we find

 x P(x)
-7 0 
 -6 1369
 -5 1352
 -4 867
 -3 400
 -2 125
 -1 24
0 7
1 32
2 225
3 1000
4 3179
5 8112
6 17797
7 35000

So: one real root: 7 and 4 imaginary roots.

Answer B

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1 year ago

The mass of a cylinder made of barium with a height of 2 inches depends on the radius of the cylinder as defined by the function

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Answer:

$r=22.07\ in$

Step-by-step explanation:

The correct function is

$m(r)=7.188\pi r^{2}$

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System of equations

$m=7.188\pi r^{2}$ -----> equation A

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2 years ago

Read 2 more answers

the sum of the two trains is 723.5 mph if the speed of the first train is 12.5 mph faster than that of the second train find the

jonny [76]

First, let's see if we can rewrite this word problem a little bit more mathematically. We won't get to mathy or technical so no worries. We just want to look at it in a more straightforward way, if we can.

Train A's mph plus Train B's mph summed equal 723.5 mph. Train A's mph is greater than Train B's mph by 12.5 mph.
So what should we do to solve this problem? Since we are dealing with two of something and we know the value of the two combined, it might make sense to start by dividing that value by 2.
723.5 / 2 = 361.75. If the two trains were travelling at the same speed, we would be done. Unfortunately, they are not so we need to think about this some more.
Train A is going 12.5 mph faster than Train B. Let's rewrite.
Train A mph = 12.5 + 361.75 = 374.25 Okay, so Train A is travelling at a speed of 374.25 mph. So we're done right? Not exactly. We are asked to fing the speeds of BOTH trains. How do we find the speed of Train B? We have added a portion of the combined total to Train A. It seems to follow, then, we should probably subtract the same portion from Train A. What are we going to do? You guessed it! Rewrite.
Train B mph = 361.75 - 12.5 = 349.25 HA HA! We seem to have figured it out. Let's do one last thing to check our work. Let's add the two trains' speeds together. If we did this right, we should get our summed value of 723.5 mph
374.25 + 349.25 = 723.5
Pat yourself on the back! We did it!

374.25 + 349.25 =

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2 years ago

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