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vekshin1
2 years ago
6

A boy moves down a waterslide from a height of 10 meters. what is his velocity when he hits the water at the bottom of the slide

?
Physics
1 answer:
statuscvo [17]2 years ago
5 0

The velocity of the boy when he hits the water at the bottom of the slide is 14 m/s.

<h3>Velocity of the boy at the bottom of the slide</h3>

The velocity of the boy when he hits the water at the bottom of the slide is calculated from the principle of conservation of energy.

K.E = P.E

¹/₂mv² = mgh

v² = 2gh

v = √2gh

where;

  • h is height of the boy
  • g is acceleration due to gravity

v = √(2 x 9.8 x 10)

v = 14 m/s.

Thus, the velocity of the boy when he hits the water at the bottom of the slide is 14 m/s.

Learn more about velocity here: brainly.com/question/6504879

#SPJ1

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What magnification will be produced by a lens of power –4.00 D (such as might be used to correct myopia) if an object is held 43
kiruha [24]

Answer:

The magnification is m  = 0.3674

Explanation:

From the question we are told that

  The  power of the lens is  P = -4.00 D(dioptre)

Generally  1 dioptre = 1 \ meter

  The object distance is u =  -43 \ cm the negative sign is because the distance is measured in the opposite direction of incident light (i.e away )

 Generally the focal length is mathematically represented as

          f = \frac{1}{P}  

   =>f = \frac{1}{4.00 }  

  =>  f = 0.25 \ m

converting to  cm  

 =>   f = 0.25 \ m = 0.25 * 100 = 25 \ cm

Generally from lens equation  we have that  

     \frac{1}{f} +\frac{1}{v} -\frac{1}{u}

=>  \frac{1}{25} +\frac{1}{v} -\frac{1}{-43}

=>   v =  -15.8 \ cm

Generally the magnification is mathematically represented as

      m  = \frac{v}{u}

=>    m  = \frac{- 15.8}{-43}

=>    m  = 0.3674

6 0
3 years ago
What are the characteristics of high energy wave?
Ivahew [28]

Answer:

D. High frequency and short wavelengths.

Explanation:

If a wave is high in energy it will have a higher frequency.

High frequency = short wavelengths

8 0
2 years ago
Somebody please explain how to solve this. Thanks in advance!
Jobisdone [24]

work done is product of force and displacement of point of application of force

so here we have to check the product of force and displacement both

Now we will put the least to maximum work in the following order

1. -A man exerts strenuous effort in pushing a stationary wall

2. -A flea pushes a speck of dirt 1 cm

3. -A farmer pushes a 2 kg wheelbarrow 20 m

4. -A cannon launches a 3 kg cannonball a distance of 200

5. -A 2000 kg car travels 400 m down a road

6. -Space shuttle Atlantis launches from the ground into near-Earth orbit

5 0
3 years ago
A gymnast of mass 63.0 kg hangs from a vertical rope attached to the ceiling. You can ignore the weight of the rope and assume t
Sergio [31]

Answer:

Explanation:

A ) When gymnast is motionless , he is in equilibrium

T = mg

= 63 x 9.81

= 618.03 N

B )

When gymnast climbs up at a constant rate , he is still in equilibrium ie net force acting on it is zero as acceleration is zero.

T = mg

= 618.03 N

C ) If the gymnast climbs up the rope with an upward acceleration of magnitude 0.600 m/s2

Net force on it = T - mg   , acting in upward direction

T - mg = m a

T =  mg + m a

= m ( g + a )

= 63 ( 9.81 + .6)

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D )  If the gymnast slides down the rope with a downward acceleration of magnitude 0.600 m/s2

Net force acting in downward direction

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T = m ( g - a )

= 63 x ( 9.81 - .6 )

= 580.23 N

6 0
3 years ago
The pointer of an analog meter is connected to a
dangina [55]
C. coil suspended by bearings. 
<span>but im not 100% sure</span>
8 0
3 years ago
Read 2 more answers
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