Answer:
k = 2
L = 8
M = 18
N = 32
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Answer:
The force needed to keep the puck sliding at constant velocity is 0N
Explanation:
Since the ice friction and air resistance are neglected, the force needed to keep the puck sliding at constant velocity is 0N.
The acceleration due to gravity (g) will be zero since there is no ice friction and air resistance taken into consideration, and therefore,
F = m*g = m*0 = 0N
Answer:
a)21.756 J
b)33.516 J
c)11.52 J
d)-1
Explanation:
Net fall in height of ball= 5.70-2.0= 3.70 m
a) work done by the force of gravity on the ball = Mg*h = 0.6×9.8×3.7 = 21.756 J
b) gravitational potential energy of the ball-earth system, relative to the ground when it is released = 0.6×9.8×5.70 = 33.516 J (ans)
c) the gravitational potential energy of the ball-earth system, relative to the ground when it is caught = 0.6×9.8×2 = 11.52 J
d) ratio of the change (PE_f − PE_0) in the gravitational potential energy of the ball-earth system to the work done on the ball by the force of gravity = (11.52 -33.51)/(21.756) ≅-1 (ans)
Answer:
The answer is below
Explanation:
The question is not complete since the liquid density is not given.
Archimedes principle states that a body at rest in a fluid is acted upon by an upward force known as the buoyant force. The buoyant force is equal to the weight of the fluid displaced.
An object floats when it is placed in a liquid only if the density of the object is less than the density of the liquid. Therefore those metals with density less than that of mercury would float while those with density greater than mercury would sink.