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Vikki [24]
4 years ago
9

The center of the Hubble space telescope is 6940 km from Earth’s center. If the gravitational force between Earth and the telesc

ope is 9.21 × 104 N, and the mass of Earth is 5.98 × 1024 kg, what is the mass of the telescope? Round the answer to the nearest whole number.
Physics
2 answers:
Ivan4 years ago
8 0

11121 kg is the answer

Law Incorporation [45]4 years ago
6 0
The gravitational force between two objects is given by:
F=G \frac{m_1 m_2}{r^2}
where
G is the gravitational constant
m1 and m2 are the masses of the two objects
r is the separation between the two objects

The distance of the telescope from the Earth's center is r=6940 km=6.94 \cdot 10^6 m, the gravitational force is F=9.21 \cdot 10^4 N and the mass of the Earth is m_1=5.98 \cdot 10^{24} kg, therefore we can rearrange the previous equation to find m2, the mass of the telescope:
m_2 =  \frac{Fr^2}{Gm_1}= \frac{(9.21 \cdot 10^4 N)(6.94\cdot 10^6)^2}{(6.67\cdot 10^{-11})(5.98\cdot 10^{24})} =11121 kg
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Answer:

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3 years ago
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Verdich [7]

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Explanation:

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I = \Delta p\\F \Delta t = m \Delta v

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F is the average breaking force

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F=\frac{m \Delta v}{\Delta t}=\frac{(1000 kg)(-10 m/s)}{5 s}=-2000 N

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4 years ago
Think about your displacement at three different times throughout your day and compare it with the distance you traveled.
Paul [167]

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6 0
4 years ago
the particles that make up a rock are constantly in motion however a rock does not visibly vibrate. why do you think this?
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I think this is because the particles don't know or care about each other,
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3 0
3 years ago
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kifflom [539]

Answer:

What to include in the answer:

Results from edg 2022

Explanation:

Did you include this in your answer?

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8 0
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