Answer:
the power of the solar cell is 1.5 watts
Explanation:
Recall that power is defined as the product of the voltage (V) times the running current (I): Power = V * I.
The only thing we have to take care of before actually performing the operation, is to convert milliamps into Amps, so our answer comes directly in the appropriate units (Watts). 500 mAmps can be written as 0.5 Amps, then, the product becomes:
Power = V * I = 3 V * 0.5 Amps = 1.5 watts
True: All matter on earth is made up of atoms.
False: Subatomic particles don't identify an element. I give you an electron. Can you tell me where it came from?
False: (1/2) A neutron has no charge [That's the True part]. It identifies the element. (Not true).
True: description of an electron.
True: description of a proton
Answer:
ENERGY AND COST. One kllowatt hour is 1,000 watts of power for one hour of time. ... Determine power: P = V XI ... Calculate the total kilowatt hours used. ... If the electric costs are 150 per kWh, how much does it cost to run the refrigerator in ... 8. A room was lighted with three 100-watt bulbs for 5 hours per day. If the cost of.
Explanation:
The rms voltage output of the generator is 1.94 × 10⁻ ⁵ V.
RMS is an acronym for root mean squared. An RMS value is more than just the "amount of AC power that causes the same heating impact as an analogous DC power" or something along those lines.
No. of loop = 795
Diameter of the coil = 10.5 cm
Radius of the coil = 5.25 cm
Magnetic Field, B = 0.45 T
Time, t = 70.0 rev/s
Where,
N = No. of loop
A = Area of the coil
B = Magnetic Field
= Voltage rms
Area of the coil = πr²
= 86.57 cm²
w = 2π/t
=( 2 × 3.141)/70.0
= 0.089
Therefore, the rms voltage output of the generator is 1.94 × 10⁻ ⁵ V.
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The complete observation about adding bulb 3 is the brightness of the bulbs has to do with power which considers both the voltage and the current: less voltage x less current = dimmer bulbs. In circuit A, the voltage is divided across the resistors and the current decreases as resistance increases. In circuit B, the voltage is the same in each parallel section of the circuit and the current through that section of the circuit only depends on the resistor in that section.
<h3>What is power of the circuit?</h3>
The power of the bulb or any resistor is equal to the product of voltage and current flowing through it.
P = VI
Circuit A has bulbs in series while the circuit B has bulbs in parallel.
When bulb 3 added to circuit A, the brightness of all the bulbs dimmed but when bulb 3 (R3) added to circuit B, nothing changed in the brightness of the bulb.
The brightness is depended on the power of the circuit. When both the voltage and current are less, the bulb will be dimmed. In circuit A, series resistors divide the voltage across them. In circuit B, voltage is equal for all the resistors.
Thus, the last option is correct.
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, the gravitational force is 
and the mass of the Earth is 
, therefore we can rearrange the previous equation to find m2, the mass of the telescope: