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Vikki [24]
3 years ago
9

The center of the Hubble space telescope is 6940 km from Earth’s center. If the gravitational force between Earth and the telesc

ope is 9.21 × 104 N, and the mass of Earth is 5.98 × 1024 kg, what is the mass of the telescope? Round the answer to the nearest whole number.
Physics
2 answers:
Ivan3 years ago
8 0

11121 kg is the answer

Law Incorporation [45]3 years ago
6 0
The gravitational force between two objects is given by:
F=G \frac{m_1 m_2}{r^2}
where
G is the gravitational constant
m1 and m2 are the masses of the two objects
r is the separation between the two objects

The distance of the telescope from the Earth's center is r=6940 km=6.94 \cdot 10^6 m, the gravitational force is F=9.21 \cdot 10^4 N and the mass of the Earth is m_1=5.98 \cdot 10^{24} kg, therefore we can rearrange the previous equation to find m2, the mass of the telescope:
m_2 =  \frac{Fr^2}{Gm_1}= \frac{(9.21 \cdot 10^4 N)(6.94\cdot 10^6)^2}{(6.67\cdot 10^{-11})(5.98\cdot 10^{24})} =11121 kg
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A conveyor belt is used to move sand from one place to another in a factory. The conveyor is tilted at an angle of 18° above the
brilliants [131]

Answer:

x = 2.044 m

Explanation:

given data

initial vertical component of velocity = Vy = 2sin18

initial horizontal component of velocity = Vx = 2cos18

distance from the ground yo = 5m

ground distance y = 0

from equation of motion

y = yo+ V_y t +\frac{1}{2}gt^2

0 = 5 + 2sin18+ \frac{1}{2}*9.8t^2

solving for t

t = 1.075 sec

for horizontal motion

x = V_x t

x = 2cos18*1.075

x = 2.044 m

8 0
3 years ago
The number of flowers on different breeds of bushes in a greenhouse is recorded every week for two months.
IceJOKER [234]

Is there a equation or something so I can do the math of how many flowers there are at the end of the two monthsm

6 0
3 years ago
Plaease help me with thesse four 40 points
Zielflug [23.3K]

Answer:

For the first one c is the answer

For the second one c is also the answer

For the third one is b

Explanation:

I took that

3 0
2 years ago
Which of the following are properties of mechanical waves?
yuradex [85]

The properties of mechanical waves are : ( C and D )

  • The three categories of mechanical waves are transverse, longitudinal,surface waves ( C )
  • Waves transport energy,but not matter ( D )

<h3>What are mechanical waves ?</h3>

Mechanical waves are a category of waves which cannot transmit energy through a vacuum, i.e. they require a medium to transmit their energy from one end to another. An example of a mechanical wave is : sound wave. Mechanical waves are grouped into transverse, longitudinal and surface waves.

Hence we can conclude that The properties of mechanical waves are : The three categories of mechanical waves are transverse, longitudinal,surface waves and Waves transport energy,but not matter

Learn more about mechanical waves : brainly.com/question/26116832

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6 0
2 years ago
The rope of a swing is 3.10 m long. Calculate the angle from the vertical at which a 76.0 kg man must begin to swing in order to
kakasveta [241]

Answer:

The angle from the vertical is 48.72°

Explanation:

Given :

Length of rope l = 3.10 m

Mass of man m = 76 Kg

Mass of car M = 1520 Kg

Velocity of car v = 1.01 \frac{m}{s}

According to conservation law,

Potential energy of man is converted to kinetic energy of car moving,

   \frac{1}{2} M v^{2} = mgh

We calculate height,

   h = \frac{M v^{2} }{2mg}

   h = \frac{1520(1.01)^{2} }{2\times 75 \times 9.8}                      ( ∵ g = 9.8 \frac{m}{s^{2} } )

   h = 1.05 m

This is the distance of the rope at the bottom,

So we take difference of it.

⇒ 3.10 - 1.05 = 2.05

We can calculate angle between them,

\cos \theta = \frac{2.05}{3.10}  = 0.6597

 \theta = 48.72°

Therefore, the angle from the vertical is 48.72°

8 0
3 years ago
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