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2 years ago

According to Newton's 3rd law of motion, if you hit a baseball with a bat it will _____.

2 answers:

4 0

Fly in a straight line unless an outside force changes its course because i tried it once in a baseball game that my mommy rekt me in.

max2010maxim [7]2 years ago

3 0

Answer:

Newton's third law of motion states every action has equal and opposite reaction.

So, according to that the baseball will have opposite reaction on the bat

So, among all the options it will hurt your hand because it will have opposite reaction on hand by bat.

In newton law the interaction of one object with second object Where action is the force on one object

And the force applied by one object on second object is the reaction.

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A small ball is attached to one end of a spring that has an unstrained length of 0.169 m. The spring is held by the other end, a

Nadya [2.5K]

The ball moves around in circular motion. The centripetal force keeping it in circular motion is given by:

F = mv²/r

F = centripetal force, m = mass of ball, v = velocity of ball, r = radius of motion

The force the spring exerts on the ball is given by:

F = kΔx

F = spring force, k = spring constant, Δx = change of spring length

The spring provides the centripetal force that keeps the ball in circular motion, so set the spring force equal to the centripetal force:

kΔx = mv²/r

Let's do some algebra:

m/k = rΔx/v²

Now if we attach the same spring to the ceiling with the ball still fixed to one end and let the ball hang in static equilibrium, the spring force would balance the ball's weight:

kΔx' = mg

k = spring constant, Δx' = new change in spring length, m = mass, g = gravitational acceleration

Let's do some more algebra:

Δx' = gm/k

Substitute m/k with our previous result, rΔx/v²:

Δx' = grΔx/v²

Given values:

g = 9.81m/s²

r = 0.169m + 0.0131m = 0.1821m

Δx = 0.0131m

v = 3.15m/s

Plug in the values and solve for Δx':

Δx' = 9.81(0.1821)(0.0131)/3.15²

Δx' = 0.0024m

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3 years ago

A rocket is dropped out of an airplane at 100 m/s (downward). If the rocket fires causing an upward acceleration of Ct2 and it t

Mkey [24]

Answer:

C = 0.0125 m/s⁴. The calculation procedure can be found in the attachment below. The concept of motion along a straight line with constant acceleration has been applied to solve the problem.

Explanation:

The sign convention chosen in this problem solution is upwards as positive and downwards negative. The equation of motion v = u + at has been used to calculate the constant C as only one unknown is contained in this equation. This is so because we have been given the initial velocity, the acceleration and the time taken. To solve future problems of this kind, first thing to check for is an equation of motion with the least number of unknown. This helps to reduce the complexity of the problem solution.

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3 years ago

Which planet has the closest gravitational pull to earth

Firdavs [7]

Answer:

venus

Explanation:

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2 years ago

Read 2 more answers

A rock rolls down a hill. Which form of energy is this an example of? (2 points)

Bond [772]

Answer:

c.Mechanical

Explanation:

6 0

3 years ago

Question 4. A tuning fork ‘A’ produces 6 beats/sec with another fork ‘B’ of un-known frequency. On

8090 [49]

Clever problem.

We know that the beat frequency is the DIFFERENCE between the frequencies of the two tuning forks. So if Fork-A is 256 Hz and the beat is 6 Hz, then Fork-B has to be EITHER 250 Hz OR 262 Hz. But which one is it ?

Well, loading Fork-B with wax increases its mass and makes it vibrate SLOWER, and when that happens, the beat drops to 5 Hz. That means that when Fork-B slowed down, its frequency got CLOSER to the frequency of Fork-A ... their DIFFERENCE dropped from 6 Hz to 5 Hz.

If slowing down Fork-B pushed it CLOSER to the frequency of Fork-A, then its natural frequency must be ABOVE Fork-A.

The natural frequency of Fork-B, after it gets cleaned up and returns to its normal condition, is 262 Hz. While it was loaded with wax, it was 261 Hz.

4 0

3 years ago