The answer to this answer choice is A. (45x12)+75=c
Dale drove to the mountains last weekend. there was heavy traffic on the way there, and the trip took 7 hours. when dale drove home, there was no traffic and the trip only took 5 hours. if his average rate was 18 miles per hour faster on the trip home, how far away does dale live from the mountains? do not do any rounding.
Answer:
Dale live 315 miles from the mountains
Step-by-step explanation:
Let y be the speed of Dale to the mountains
Time taken by Dale to the mountains=7 hrs
Therefore distance covered by dale to the mountain = speed × time = 7y ......eqn 1
Time taken by Dale back home = 5hours
Since it speed increased by 18 miles per hour back home it speed = y+18
So distance traveled home =speed × time = (y+18)5 ...... eqn 2
Since distance cover is same in both the eqn 1 and eqn 2.
Eqn 1 = eqn 2
7y = (y+18)5
7y = 5y + 90
7y - 5y = 90 (collection like terms)
2y = 90
Y = 45
Substitute for y in eqn 1 to get distance away from mountain
= 7y eqn 1
= 7×45
= 315 miles.
∴ Dale leave 315 miles from the mountains
New length = 30x110% = 33cm
new width = 20x105% = 21cm
original perimeter = 30x2 + 20x2
= 60 + 40 = 100
new perimeter = 33x2 + 21x2
= 66 + 42 = 108
increase in perimeter = 108-100 = 8
percentage increase = 8/100 x 100% = 8%
All you need to do is convert this to Kelvin.
Add 273.15 to Celcius to find Kelvin.
255.15 kelvin
Answer:
C. 0.23°
Step-by-step explanation:
We are given
Re-arranging this equation (multiply by 32 on both sides and divide by 
on both sides gives us:
or
Substituting for, r and v we get
