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antiseptic1488 [7]
1 year ago
6

The average weight of full-grown beef cows is 1,470 pounds with a standard deviation of 230 pounds. if the weights are normally

distributed, what is the percentile rank of a cow that weighs 1,750 pounds? (1) 89th (2) 76th (3) 49th (4) 35th
Mathematics
1 answer:
creativ13 [48]1 year ago
8 0

Answer: The percentile is 89

Step-by-step explanation:

This question can be solved using concept for t tables

In a normal distribution the curve. \mu= 1470 ,  \sigma = 230, x=1750

The relationship between z score, mean and standard deviation is given by

x = \mu+z\sigma

So the z value according to this is given by the formula

1750=1470+z(230)\\ z=\frac{280}{230} \\\\z = 1.217

From the z table we can infer that p value for z=+1.217 is 88.82

So 1750 is 89th percentile

To learn more about statistics, visit brainly.com/question/26352252

#SPJ4

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Hey!

3x-5=1

-5 to the other side as +5

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x=2

Good luck

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You can rewrite all that repeated multiplication as *exponents*, which is why we call it exponential growth.

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3 years ago
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8 0
3 years ago
30 seconds of 2.5 mins in percentage
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Read 2 more answers
Justin walked 3 miles north and 6 miles west. starting from the same point, tina walked 2 miles south and 4 miles east. how far
Darya [45]
Basically, Justin and Tina's paths form two right-angled triangles whose hypotenuses(?) form a straight line between their end points. Therefore we need to find the two distances from the starting point and add them.
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