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SpyIntel [72]
2 years ago
8

Al+HCl=AlCl6+H6is this balanced or unbalanced ​

Chemistry
1 answer:
yarga [219]2 years ago
4 0

Answer:

unbalanced

Explanation:

balanced: Al+HCl=AlCl+H

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Just as the depletion of stratospheric ozone today threatens life on Earth today, its accumulation was one of the crucial proces
inessss [21]

Answer:

(a) rate = -(1/3) Δ[O₂]/Δt = +(1/2) Δ[O₃]/Δt  

(b) Δ[O₃]/Δt = 1.07x10⁻⁵ mol/Ls

Explanation:

By definition, t<u>he reaction rate for a chemical reaction can be expressed by the decrease in the concentration of reactants or the increase in the concentration of products:</u>    

aX → bY (1)

rate= -\frac{1}{a} \frac{\Delta[X]}{ \Delta t} = +\frac{1}{b} \frac{\Delta[Y]}{ \Delta t}

<em>where, a and b are the coefficients of de reactant X and product Y, respectively.        </em>

(a) Based on the definition above, we can express the rate of reaction (2) as follows:      

3O₂(g) → 2O₃(g) (2)    

rate = -\frac{1}{3} \frac{\Delta[O_{2}]}{\Delta t} = +\frac{1}{2} \frac{ \Delta[O_{3}]}{ \Delta t} (3)

(b) From the rate of disappearance of O₂ in equation (3), we can find the rate of appearance of O₃:  

rate = +\frac{1}{2} \frac{\Delta[O_{3}]}{ \Delta t} = -\frac{1}{3} \frac{\Delta[O_{2}]}{ \Delta t}

+\frac{\Delta[O_{3}]}{ \Delta t} = -\frac{2}{3} \frac{\Delta[-1.61 \cdot 10^{-5}]}{ \Delta t}          

\frac{\Delta[O_{3}]}{ \Delta t} = 1.07 \cdot 10^{-5} \frac{mol}{Ls}

So the rate of appearance of O₃ is 1.07x10⁻⁵ mol/Ls.

           

Have a nice day!

6 0
4 years ago
For the reaction of oxygen and nitrogen to form nitric oxide, consider the following thermodynamic data: ΔH∘rxn 180.5 kJ/mol ΔS∘
nasty-shy [4]

Answer:

7.28 × 10³ K

Explanation:

Let's consider the following reaction.

N₂(g) + O₂(g) → 2 NO(g)

The reaction is spontaneous when the standard Gibbs free energy (ΔG°) is negative. ΔG° is related to the standard enthalpy of the reaction (ΔH°) and the standard entropy of the reaction (ΔS°) through the following expression.

ΔG° = ΔH° - T . ΔS°

If ΔG° < 0,

ΔH° - T . ΔS° < 0

ΔH° < T . ΔS°

T > ΔH°/ΔS° = (180.5 × 10³ J/mol)/(24.8 J/mol.K) = 7.28 × 10³ K

The reaction is spontaneous above 7.28 × 10³ K.

7 0
4 years ago
Help with a and b if so thanks please asap!!
Anastaziya [24]

Answer:

A.  0.01  B. 650

Explanation:

I love helping people.

7 0
4 years ago
Solubility is usually expressed as the maximum number of grams of
Aleonysh [2.5K]

We usually expess solubility as the maximum number of grams of of a solute that will dissolve in 100 g of solvent.

For example, at 20 °C, the solubility of <em>sodium chloride</em> is <em>35.89 g/100 g water</em>.

7 0
4 years ago
An element consists of two isotopes. The abundance of one isotope is 95.72% and its atomic mass is 114.9041 u. The atomic mass o
meriva

Answer:

d. 114.8 u

Explanation:

The formula for the calculation of the average atomic mass is:

Average\ atomic\ mass=(\frac {\%\ of\ the\ first\ isotope}{100}\times {Mass\ of\ the\ first\ isotope})+(\frac {\%\ of\ the\ second\ isotope}{100}\times {Mass\ of\ the\ second\ isotope})

Given that:

<u>For first isotope: </u>

% = 95.72 %

Mass = 114.9041 u

<u> For second isotope: </u>

Since the element has only 2 isotopes, so the percentage of second is 100 - first percentage.

% = 100 %  - 95.72 %  = 4.28 %

Mass = 112.9043 u

Average Mass = ?

Thus,  

Average\ atomic\ mass=\frac {95.72}{100}\times {114.9041}+\frac {4.28}{100}\times {112.9043}\ u

<u>Average atomic mass = 114.8 u</u>

3 0
3 years ago
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