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dangina [55]
3 years ago
8

Solubility is usually expressed as the maximum number of grams of

Chemistry
1 answer:
Aleonysh [2.5K]3 years ago
7 0

We usually expess solubility as the maximum number of grams of of a solute that will dissolve in 100 g of solvent.

For example, at 20 °C, the solubility of <em>sodium chloride</em> is <em>35.89 g/100 g water</em>.

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Explain how creativity can play a role in the construction of scientific questions and hypotheses.
sweet-ann [11.9K]
Scientific questions and hypotheses come up frequently while one is engaged in investigating a scientific phenomenon such  as natural geological phenomena as may occur in geological mapping in the field. For example, there may be a question does this canyon or deeply incised valley which is quite straight follow a weakness in the earth's crust like a major fault or the direction of bedding in well bedded sedimentary rocks. In a particular topographic area, some hypotheses which may be developed is that valleys follow geological structure whereas ridges follow resistant rocks like quartzites or quartz sandstones or in the ocean, points or capes may represent resistant quartz sandstones and bays may represent weak soft shales recessively weathering
4 0
3 years ago
How do you raise the boiling point of a liquid?
Naddika [18.5K]
Raise the boiling temperature
6 0
3 years ago
What is the percentage yield of O2 if 12.3 g of KClO3 (molar mass 123 g) is decomposed to produce 3.2 g of O2 (molar mass 32 g)
My name is Ann [436]

Answer:

The percentage yield of O2 is 66.7%

Explanation:

Reaction for decomposition of potassium chlorate is:

2KClO₃ →  2KCl  +  3O₂

The products are potassium chloride and oxygen.

Let's find out the moles of chlorate.

Mass / Molar mass = Moles

12.3 g / 123 g/mol = 0.1 mol

So ratio is 2:3, 2 moles of chlorate produce 3 mol of oxygen.

Then, 0.1 mol of chlorate may produce (0.1  .3)/ 2 = 0.15 moles

Let's convert the moles of produced oxygen, as to find out the theoretical yield.

0.15 mol . 32 g/ 1mol = 4.8 g

To calculate the percentage yield, the formula is

(Produced Yield / Theoretical yield) . 100 =

(3.2g / 4.8g) . 100 = 66.7 %

8 0
3 years ago
What volume of 0.500 M HNO3(aq) must completely react to neutralize 100.0 milliliters of 0.100 M KOH(aq)?
asambeis [7]
KOH+ HNO3--> KNO3+ H2O<span>
From this balanced equation, we know that 1 mol HNO3= 1 mol KOH (keep in mind this because it will be used later).

We also know that 0.100 M KOH aqueous solution (soln)= 0.100 mol KOH/ 1 L of KOH soln (this one is based on the definition of molarity).

First, we should find the mole of KOH:
100.0 mL KOH soln* (1 L KOH soln/ 1,000 mL KOH soln)* (0.100 mol KOH/ 1L KOH soln)= 1.00*10^(-2) mol KOH.

Now, let's find the volume of HNO3 soln:
1.00*10^(-2) mol KOH* (1 mol HNO3/ 1 mol KOH)* (1 L HNO3 soln/ 0.500 mol HNO3)* (1,000 mL HNO3 soln/ 1 L HNO3 soln)= 20.0 mL HNO3 soln.

The final answer is </span>(2) 20.0 mL.<span>

Also, this problem can also be done by using dimensional analysis. 

Hope this would help~ </span>
6 0
3 years ago
Your teacher asks you to design an experiment that shows how plants respond to changes in their environment. You have two identi
tia_tia [17]

Answer:

1.  Make observations.

Determine whether the plant grown under the white light bulb or the plant grown under the red light bulb grew better.

Observations are anything we notice which lead to a question in our mind.

2. Ask a question.

Do plants grow as well under a different color of light?

As this is a question being asked, hence it will be the question for the scientific method of research.

3. Test the hypothesis.

Put one plant under a white light bulb, and  place the other plant under a red light bulb.  Measure the growth of the two plants.

To test the hypothesis, experiments are performed. This is the experiment.

4. Analyze the results, and make a conclusion.

Plants grow well under sunlight or a light bulb  with a hot, white light.

After the experiments, the results are compiled and a conclusion is drawn.

5. Test or modify.

If you observe no change, repeat the experiment with different colors of light bulbs. If there is a change, repeat the experiment for one or two more trials to ensure that the color of the light bulb contributes to the change.

If our hypothesis does not come out to be true, then another hypothesis can be generated and tests be done for it.

6 0
3 years ago
Read 2 more answers
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