Answer:
Density of Radon is 5.44 g/.
Explanation:
Given data:
Temperature of gas = 100°C (273+100 = 373 K)
Pressure of gas = 0.75 atm
Density of gas = ?
Solution:
First of all we will derive the formula.
We know that,
PV = nRT
and
n = m/M (m = mass, M = molar mass)
PV = (m/M) RT
PVM = (m/M) RT ×M
PVM = mRT
PVM/V = mRT/V
PM = dRT (m/V = d)
Now we will put the values in formula:
Molar mass of Radon is 222 g/mol .
0.75 atm ×222 g/mol = d× 0.0821 atm.L/mol.K ×373 K
166.5 atm.g/mol = d×30.62 atm.L/mol
d = 166.5 atm.g/mol / 30.62 atm.L/mol
d = 5.44 g/L
Answer:
58.92 g EDTA
Explanation:
315.1 mL = .3151 L
M = Moles / Liter
.3151 L x <u>0.5 mol EDTA</u> x <u>374 g EDTA</u> = 58.92 g EDTA
1 L EDTA 1 mol EDTA
Answer:2 Li+CO2+H2O=LiHCO3+H2
Explanation:
Answer:
ClAl
Explanation:
* = electron
Cl (17) * * * * * * *
Al (13) * * *
If one of aluminum's electrons were added to chlorine to make a full shell, still have 2 left over. So you need another:
Cl * * * * * * * * (full)
Cl * * * * * * *
Al * *
Still have another left over. Aluminum needs to lose another one of its valence electrons to be able to have a full shell. So you take another chlorine:
Cl * * * * * * * * (full)
Cl * * * * * * * * (full)
Cl * * * * * * *
Al *
You will eventuate with 3Cl and 1Al, or ClAl. Modeled above:
Is correct hope this helps i have done this before