The correct answer is option E.
Explanation:
The pH of the solution is defined as negative logarithm of hydrogen ions concentration in a solution. Mathematically written as:
![pH=-\log[H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%5BH%5E%2B%5D)
The pOH of the solution is defined as negative logarithm of hydroxide ions concentration in a solution. Mathematically written as:
![pOH=-\log[OH^-]](https://tex.z-dn.net/?f=pOH%3D-%5Clog%5BOH%5E-%5D)
The sum of ph and pOH is equal to 14.
pH + pOH = 14
A solution has a pH of 4.20.
![pOH=9.8=-\log[OH^-]](https://tex.z-dn.net/?f=pOH%3D9.8%3D-%5Clog%5BOH%5E-%5D)
![[OH^-]=1.58\times 10^{-10} M\approx 6.0\times 10^{-10} M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D1.58%5Ctimes%2010%5E%7B-10%7D%20M%5Capprox%206.0%5Ctimes%2010%5E%7B-10%7D%20M)
Hence, the correct answer is option E.
Answer:
The amount of isopropyl alcohol contained in 150 ml of the solution is 117.15 grams
Explanation:
The density of a substance is the mass per unit volume, therefore, we have;
The density of the isopropyl alcohol = 0.785 g/ml at 25°C
The density = mass/volume
Mass = Density × Volume
The mass of the 150 ml of isopropyl alcohol is therefore;
Mass = 0.785 g/ml × 150 ml = 117.15 g
The amount in grams contained in 150 ml of sample = 117.15 g.
Answer:
Explanation:
reduction potential of NO gas is highly unfavourable . It is - 1.7 V . So it is highly unlikely to be reduced to NO⁻ . On the other hand it is easily oxidised .
Half cell reaction of given cell
At anode ( where oxidation occurs )
NO⁻ ⇒ NO + e ( reduction potential is - 1.7 V )
At cathode ( where reduction takes place )
Br₂ + 2e ⇒2 Br⁻ ( reduction potential is 1.09 V )
(NO⁻ ⇒ NO + e ) x 2
Br₂ + 2e ⇒2 Br⁻
--------------------------------
Br₂ + 2NO⁻ ⇒ 2NO +2 Br⁻
Ecell = Ecathode - E anode
= 1.09 - 2 x ( - 1.7)
4.5 V
