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juin [17]
3 years ago
8

Jis a colourless solid. When it is warmed with sodium hydroxide solution it

Chemistry
1 answer:
Alona [7]3 years ago
6 0

Answer:

i am sorry i do not know the answer

Explanation:

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Why wasn't the water pasteurized
elixir [45]

Answer: who knows..

Explanation:

7 0
3 years ago
A wave is best defined as
vladimir1956 [14]

Answer:

A wave is a physical phenomenon characterized by its frequency, wavelength, and amplitude. In general, waves transfer energy from one location to another, in which case they have a velocity. Standing waves may also occur; these have no net velocity and involve no net transfer of energy.

3 0
3 years ago
How many grams of ammonia (NH3) are present in 5.0L of a 0.050M Solution?
MissTica

Answer:

B

Explanation:

NH3 in a liter is 17 x 0.05 = 0.85g

In 5L = 0.85 x 5 = 4.25 = 4.3g

3 0
3 years ago
Read 2 more answers
Equal amounts of N2 and O2 are added, under certain conditions, to a closed container. Which changes occur in the reverse reacti
geniusboy [140]
1) The forward reaction is N2 (g) + O2 (g)  → 2NO

(that reaction requires special contitions because at normal pressures and temperatures N2 and O2 do not react to form another compound.

2) The equiblibrium equation is

  N2 (g) + O2 (g)  ⇄ 2NO

3) Then, the reverse reaction is

2NO → N2(g) + O2(g)

Answer: 2NO → N2(g) + O2(g)
4 0
3 years ago
How much heat is absorbed by a 112.5 g sample of water when it is heated from 12.5 °C to 9°C? (Specific heat capacity of water i
Oduvanchick [21]

Answer:

–1647.45 J

Explanation:

From the question given above, the following data were obtained:

Mass (M) = 112.5 g

Initial temperature (T₁) = 12.5 °C

Final temperature (T₂) = 9°C

Specific heat capacity (C) = 4.184 J/g°C

Heat (Q) absorbed =?

Next, we shall determine the change in temperature. This can be obtained as follow:

Initial temperature (T₁) = 12.5 °C

Final temperature (T₂) = 9°C

Change in temperature (ΔT) =?

ΔT = T₂ – T₁

ΔT = 9 – 12.5

ΔT = –3.5 °C

Finally, we shall determine the heat absorbed. This can be obtained as follow:

Mass (M) = 112.5 g

Change in temperature (ΔT) = –3.5 °C

Specific heat capacity (C) = 4.184 J/g°C

Heat (Q) absorbed =?

Q = MCΔT

Q = 112.5 × 4.184 × –3.5

Q = –1647.45 J

5 0
3 years ago
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