The combinations of Strontium and chlorine that are possible are only those in which strontium and chlorine combine in the ratio of 1:2.
1) The possible combinations are
- 4 strontium atoms and 8 chlorine
strontium atoms and
chlorine atoms
2) The combinations that are not possible are
- 20 strontium atoms and 60 chlorine atoms
- 130 billion strontium atoms and 195 billion chlorine
We have to work out the ratio of Strontium and chlorine in each of the given combinations in the question. Only the combinations in which the ratio of Strontium and chlorine is 1:2 is possible.
First case:
4 strontium atoms and 8 chlorine atoms gives a Strontium and chlorine ratio of 1:2 so it is possible.
Second case:
20 strontium atoms and 60 chlorine atoms gives a Strontium and chlorine ratio of 1:3 hence it is not possible.
Third case:
strontium atoms and chlorine atoms gives a Strontium and chlorine ratio of 1:2 hence it is possible.
Fourth case:
130 billion strontium atoms and 195 billion chlorine atoms gives a Strontium and chlorine ratio of 1:1.5 hence it is not possible.
Learn more: brainly.com/question/9743981
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Woof. Hope it helps!!! :) ....Reason*
I believe it might be A, hope this helps!
Molality= mol/ Kg
if we assume that we have 1 kg of water, we have 3.19 moles of solute.
the formula for mole fraction --> mole fraction= mol of solule/ mol of solution
1) if we have 1 kg of water which is same as 1000 grams of water.
2) we need to convert grams to moles using the molar mass of water
molar mass of H₂O= (2 x 1.01) + 16.0 = 18.02 g/mol
1000 g (1 mol/ 18.02 grams)= 55.5 mol
3) mole of solution= 55.5 moles + 3.19 moles= 58.7 moles of solution
4) mole fraction= 3.19 / 58.7= 0.0543
