Types of Bonds can be predicted by calculating the
difference in electronegativity.
If, Electronegativity difference is,
Less
than 0.4 then it is Non Polar Pure Covalent
Between 0.4 and 1.7 then it is Polar Covalent
Greater than 1.7 then it is Ionic
For Br and Br,
E.N of Bromine = 2.96
E.N of Bromine = 2.96
________
E.N Difference
0.00 (Non Polar/Pure Covalent)
For N and O,
E.N of Oxygen = 3.44
E.N of Nitrogen = 3.04
________
E.N Difference
0.40 (Non Polar/Pure Covalent)
For P and H,
E.N of Hydrogen = 2.20
E.N of Phosphorous = 2.19
________
E.N Difference 0.01 (Non Polar/Pure Covalent)
For K and O,
E.N of Oxygen = 3.44
E.N of Potassium = 0.82
________
E.N Difference 2.62 (Ionic)
The answer is 10 grams.
The atomic weights for each elements are :
<span>Na - 22.99 g/mol </span>
<span>O - 16.00 g/mol </span>
<span>H - 1.01 g/mol
The sum = 40 g/mol for NAOH
</span><span>0.250 moles * 40.00 g / 1 mole = 10 g NaOH</span>
Answer:
chemicals symbols are used for abbreviating the name of the element/chemical while chemicals formulas tell you how much of each element are in each chemical atom
Explanation:
1) is the answer because the only way to turn it from blue to yellow is to mix it with an acidic solution.
Moles 
neutralized = moles 
neutralized at the equivalence point of a titration. Hence, option A is correct.
<h3>
What is titration?</h3>
A method or process of determining the concentration of a dissolved substance in terms of the smallest amount of reagent of known concentration required to bring about a given effect in reaction with a known volume of the test solution.
Equivalence point: point in titration at which the amount of titrant added is just enough to completely neutralize the analyte solution.
At the equivalence point in an acid-base titration, moles of base = moles of acid and the solution only contains salt and water.
Hence, option A is correct.
Learn more about the titration here:
brainly.com/question/13307013
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