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Lorico [155]
2 years ago
6

A chemistry student is recording the electric charges of some atoms. Use the results in the chart to answer the following questi

ons.
Atom Electric Charge
Carbon −4
Nitrogen +5
Oxygen −2
Part A:
Write an equation to find the difference in electric charge between the Nitrogen atom and the Oxygen atom.

Part B:
Using the equation you wrote in Part A, what is the difference in electric charge between the two atoms?
Chemistry
1 answer:
o-na [289]2 years ago
4 0
Answer Can someone here please look at my questions and see if you can help
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Which of the following sequences of elements would all have four valence electrons?
timama [110]

Answer:b

Explanation:

8 0
2 years ago
Lawrencium-262 has a half-life of 4 hr. How much of a 40 mg sample remains after 12 hours?
CaHeK987 [17]

Answer:

5 mg

Explanation:

If one half life is 4 hours, then 3 half lives is 12 hours.

This means that the sample will decay to 1/8 of its original amount.

So, the answer is 40(1/8) = 5 mg.

3 0
1 year ago
What name is given to bonds that involve the sharing of electrons?
Nana76 [90]
A. Covalent bonds is the answer
4 0
3 years ago
Calculate the pH and fraction of dissociation ( α ) for each of the acetic acid ( CH 3 COOH , p K a = 4.756 ) solutions. A 0.002
marysya [2.9K]

Answer:

The degree of dissociation of acetic acid is 0.08448.

The pH of the solution is 3.72.

Explanation:

The pK_a=4.756

The value of the dissociation constant = K_a

pK_a=-\log[K_a]

K_a=10^{-4.756}=1.754\times 10^{-5}

Initial concentration of the acetic acid = [HAc] =c = 0.00225

Degree of dissociation = α

HAc\rightleftharpoons H^++Ac^-

Initially

c

At equilibrium ;

(c-cα)                                cα        cα

The expression of dissociation constant is given as:

K_a=\frac{[H^+][Ac^-]}{[HAc]}

1.754\times 10^{-5}=\frac{c\times \alpha \times c\times \alpha}{(c-c\alpha)}

1.754\times 10^{-5}=\frac{c\alpha ^2}{(1-\alpha)}

1.754\times 10^{-5}=\frac{0.00225 \alpha ^2}{(1-\alpha)}

Solving for α:

α = 0.08448

The degree of dissociation of acetic acid is 0.08448.

[H^+]=c\alpha = 0.00225M\times 0.08448=0.0001901 M

The pH of the solution ;

pH=-\log[H^+]

=-\log[0.0001901 M]=3.72

3 0
3 years ago
what is the half life isotope if after 21 days you have 31.25 g remaining from a 250.0 g starting sample size?
alexgriva [62]

250 --> 125 --> 62.5 --> 31.25


each arrow equals one half life, so 3 half lives


14 days/ 3 half lives =


4.67 days = half life

3 0
3 years ago
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