Tin is classified as a metal in family 14.
The phrase which best describes nuclear fusion is: A. the process by which small nuclei combine into a larger nucleus.
A nuclear reaction can be defined as a type of chemical reaction in which the nucleus of an atom of a radioactive chemical element is transformed by either being joined (fusion) or split (fission) with the nucleus of another atom of a radioactive chemical element and accompanied by a release of energy.
Generally, there are two (2) main types of nuclear reaction and these include:
- <u>Nuclear fission:</u> it involves the collision of a heavy atomic nucleus with a neutron, thereby causing a split and release of energy.
- <u>Nuclear fusion:</u> it involves the joining of two smaller nuclei of atoms to form a single massive or heavier (larger) nucleus with the release of energy.
In conclusion, nuclear fusion is best described as the process by which small nuclei combine into a larger nucleus, accompanied by a release of energy.
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Answer:</h3>
3CaCl₂ + 2Na₃PO₄→ Ca₃(PO₄)₂ + 6NaCl
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Explanation:</h3>
We are given the Equation;
CaCl₂ + Na₃PO₄→ Ca₃(PO₄)₂ + NaCl
Assuming the question requires us to balance the equation;
- A balanced chemical equation is one that has equal number of atoms of each element on both sides of the equation.
- Balancing chemical equations ensures that they obey the law of conservation of mass in chemical equations.
- According to the law of conservation of mass in chemical equation, the mass of the reactants should always be equal to the mass of the products.
- Balancing chemical equations involves putting appropriate coefficients on the reactants and products.
In this case;
- To balance the equation we are going to put the coefficients 3, 2, 1, and 6.
- Therefore; the balanced equation will be;
3CaCl₂ + 2Na₃PO₄→ Ca₃(PO₄)₂ + 6NaCl
Answer:
balanced equation mole ratio 5 2 mol NO/1 mol O2
10.00 g O2 3 1 mol O2/32.00 g O2 5 0.3125 mol O2
20.00 g NO 3 1 mol NO/30.01 g NO 5 0.6664 mol NO
actual mole ratio 5 0.6664 mol NO/0.3125 mol O2 5 2.132 mol NO/1.000 mol O2
Because the actual mole ratio of NO:O2 is larger than the balanced equation mole
ratio of NO:O2, there is an excess of NO; O2 is the limiting reactant.
Mass of NO used 5 0.3125 mol O2 3 2 mol NO/1 mol O2 5 0.6250 mol NO
0.6250 mol NO 3 30.01 g NO/1 mol NO 5 18.76 g NO
Mass of NO2 produced 5 0.6250 mol NO2 3 46.01 g NO2/1 mol NO2 5 28.76 g NO2
Excess NO 5 20.00 g NO 2 18.76 g NO 5 1.24 g N
Explanation:
