The system of equations shown is solved using the linear combination method

1 answer:

6 0

The 0 = 0 in the solution to the system implies that the system of equations involving the equations 6x - 5y = -8 and 6x - 5y = -8 have infinitely many solutions

<h3>What are linear equations?</h3>

Linear equations are equations that have constant average rates of change, slope or gradient

<h3>How to determine the linear combination to the system?</h3>

A system of linear equations is a collection of at least two linear equations.

In this case, the system of equations is given as

6x - 5y = -8

Subtract the equation 6x - 5y = -8 from the equation 6x - 5y = -8

6x - 5y = -8

- 6x - 5y = -8

----------------------

0 = 0

This in other words means that the difference between both equations is 0

When the solution to a system of equation is 0 = 0, it means that the system of equations have infinitely many solutions

Hence, the 0 = 0 in the solution to the system implies that the system of equations involving the equations 6x - 5y = -8 and 6x - 5y = -8 have infinitely many solutions

Read more about system of linear equations at

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Write the first five terms of the geometric sequence in which a1=8 and the common ratio is -1/2.

Oliga [24]

Answer:

First five terms are:

8 , (-4) , 2 , (-1) , (1/2)

Step-by-step explanation:

$a_{1}=8 \\\\r = \frac{-1}{2}\\\\a_{2}=\frac{-1}{2}*a_{1}= \frac{-1}{2}*8= -4\\\\a_{3}=\frac{-1}{2}*a_{2}=\frac{-1}{2}*-4=2\\\\a_{4}=\frac{-1}{2}*a_{3}=\frac{-1}{2}*2=-1\\\\a_{5}=\frac{-1}{2}*a_{4}=\frac{-1}{2}*-1=\frac{1}{2}$