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Gnesinka [82]
2 years ago
14

Assuming that the rest of the genome is normal, cells with an inactivating mutation in one copy of a tumor-suppressor gene with

the second copy of the gene still wild-type are most likely to_____.
Biology
1 answer:
BlackZzzverrR [31]2 years ago
7 0

Assuming that the rest of the genome is normal, cells with an inactivating mutation in one copy of a tumor-suppressor gene with the second copy of the gene still wild-type are most likely to show no changes in DNA sequence.

Tumor suppressor genes are normally present in the body. These function properly and keep processing the cell growth and cell death (apoptosis). It can also suppress tumor development. If both copies of a tumor suppressor gene is mutated then only it cause a change in cell growth and form a tumor. So these are recessive in nature. And if only one gene is mutated then it shows no mutation. When a tumor suppressor gene is inactivated by mutation, the protein it encodes is not produced or does not function properly, and as a result, uncontrolled cell division can occur. Such mutations can contribute to the development of cancer.

Learn more about Tumor suppressor genes on:

brainly.com/question/18649985

#SPJ4

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