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Evgesh-ka [11]
2 years ago
7

How many five-letter words (technically, we should call them strings, because we do not care if they make sense) can be formed u

sing the letters A, B, C,
Mathematics
1 answer:
andriy [413]2 years ago
8 0

Total number of five letter strings formed by A,B,C and D with repetitions allowed

={4x4x4x4x4 = 4 power 5 = 1024

Now, fix BAD in a string at one place then we have 2 more places to be filled with 4 letters, total number of such strings

=4x4=16

Here, BAD can be at any of the 3 positions,

Hence the total number of strings with BAD in it

= 3 x 16=48

Now, The total number of strings not containing BAD

=1024-48

=976

Using 26 letters, the number of 5-letter words that can be formed when the letters are different is determined as follows: 26P5 = 26 × 25 × 24 × 23 × 22 = 7883600 different words.

Learn more about five-letter strings here:brainly.com/question/27134945

#SPJ4

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Solution:

12.5 < x < 18.9

Reason:

To solve this problem, we can apply Pythagorean's theorem.

To find the upper bound:

We can set the two given legs as the 2 legs of a right triangle. This allows us to keep the angle under 90 degrees. So if we set the legs to be 10 and 16, then the third side must be:

10^2 + 16^2 = x^2

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x is roughly equal to 18.9

For the lower bound, this time, we set x as one of the legs, and 10 as the other let. Since we know that the longest side is 16, we can set up an equation again:

x^2 + 10^2 = 16^2

x^2 = 16^2 - 10^2

x^2 = 156

x is roughly equal to 12.5

So we have found the bounds to be 12.5 < x < 18.9

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3 years ago
HELPPPPPPPP!!!!!!!!!!!!!!!!!!!!!1
AlexFokin [52]

Answer:

the answer would be option 1, please mark brainliest!

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