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Tamiku [17]
2 years ago
7

The ramp has an efficiency of 80%. If you perform 600 J of work, how much useful work does the ramp do

Physics
1 answer:
PIT_PIT [208]2 years ago
5 0

The ramp does 480J of useful work with an efficiency of 80% .

<h3>What is efficiency of work done ?</h3>
  • Efficiency is the ratio of the useful energy released by a system to the input energy .
  • Mathematically, efficiency of energy = out put energy/ input energy

<h3>What is the useful work done by the ramp having efficiency 80% and an input work done 600J?</h3>
  • The efficiency =output work done/ input work done
  • 80% =output work done/ 600J
  • output work done =( 80×600)/100

=480J

Thus, we can conclude that the useful work done by the ramp is 480J.

Learn more about efficiency of energy here:

brainly.com/question/14280607

#SPJ1

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