1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
KiRa [710]
3 years ago
8

HURRY Which change is an example of transforming potential energy to kinetic energy

Physics
2 answers:
miv72 [106K]3 years ago
4 0

Answer:

The answer would be C, changing nuclear energy to radiant energy

Explanation:

Welcome have a good day.

Jet001 [13]3 years ago
3 0

Answer:

C.  changing nuclear energy to radiant energy

Explanation:

Nuclear energy takes atoms in their potential state, split them (fission) or fuse them (fusion)  creating chain reactions of radiant energy.  Most nuclear electrical power plants use fission, radiant energy heats water making steam to spin turbines.

Or think of the atom bomb.  Definitely potential energy until the fuse starts detonation and chain reactions.  The radiant kinetic energy and shock waves were horrendous.

You might be interested in
Two horizontal rods are each held up by vertical strings tied to their ends. Rod 1 has length L and mass M; rod 2 has length 2L
antiseptic1488 [7]

Answer:

Rod 1 has greater initial angular acceleration; The initial angular acceleration for rod 1 is greater than for rod 2.

Explanation:

For the rod 1 the angular acceleration is

\tau_1 = I_1\alpha _1 \\\\\alpha_1 = \dfrac{\tau_1}{I_1}

Similarly, for rod 2

\alpha_2 = \dfrac{\tau_2}{I_2}.

Now, the moment of inertia for rod 1 is

I_1 = \dfrac{1}{3}ML^2,

and the torque acting on it is (about the center of mass)

\tau_1 = Mg\dfrac{L}{2};

therefore, the angular acceleration of rod 1 is  

\alpha_1 = \dfrac{Mg\dfrac{L}{2}}{\dfrac{1}{3}ML^2},

\boxed{\alpha_1 = \dfrac{3g}{2L} }

Now, for rod 2 the moment of inertia is

I_2 = \dfrac{1}{3}(2M)(2L)^2

I_2 = \dfrac{8}{3} ML^2,

and the torque acting is (about the center of mass)

\tau _2 = (2M)g \dfrac{(2L)}{2}

\tau _2 = 2MgL;

therefore, the angular acceleration \alpha_2 is

\alpha_2 = \dfrac{2MgL;}{\dfrac{8}{3} ML^2,}.

\boxed{\alpha_2 = \dfrac{3g}{4L}}

We see here that

\dfrac{3g}{2L} > \dfrac{3g}{4L}

therefore

\boxed{\alpha_1 > \alpha_2.}

In other words , the initial angular acceleration for rod 1 is greater than for rod 2.

7 0
3 years ago
How much force is required to accelerate a 57 kg skier 4 m/s2? ______ N (do not write anything except the number)
vfiekz [6]

The amount of force required to accelerate 57kg skier with an acceleration of 4m/s² is 228N.

<h3>How to calculate force?</h3>

Force is a physical quantity that denotes ability to push, pull, twist or accelerate a body and which has a direction and is measured in a unit dimensioned in mass × distance/time².

The force applied on an object can be calculated using the following formula:

Force = mass × acceleration

According to this question, a skier with mass 57kg accelerates at 4m/s². The force required can be calculated as follows:

Force = 57kg × 4m/s²

Force = 228N

Therefore, the amount of force required to accelerate 57kg skier with an acceleration of 4m/s² is 228N.

Learn more about force at: brainly.com/question/1046166

#SPJ1

7 0
2 years ago
The electrostatic force between two charges located 2 meters apart is 0.10 N. What will the force be between these charges when
Vikentia [17]
Given that 2 m is to .10N

we will set up a ratio & proportion

.10 x
— —
2 1

cross multiply

2x = .10(1)

divide both sides by 2

x (and the answer) = .05 N

6 0
3 years ago
A slide 4.1 meters long makes an angle of 35° with the ground. to the nearest tenth of a meter, how far above the ground is the
melomori [17]
The given are:A
djacent/Hypotenuse = sin 35° 
Height(h) - Adjacent
Hypotenuse- a length of a side: 

We will use the formula:
sin (angle) = op/hyp
sin 35° = h/ 4.1 m
0.57356 = h / 4.1 m
h = 0.576576 ·
4.1 = 2.35166 ≈ 2.4 m

Answer: the top of the slide is 2.4 m above the ground which is letter d.
4 0
3 years ago
What is the relationship between the center of gravity and the support base for an object that is in stable equilibrium?
Norma-Jean [14]

Answer:

when the center of gravity is within the washing area, the torque returns in the body to its initial position and is in a stable equilibrium

Explanation:

The concept of center of gravity is equivalent to the concept of center of mass, in this place all external forces applied can be considered.

When we analyze the balance of a body that is the torque it is the one that defines the balance

      τ = F xd

If the torque tends to restore the body to the initial position the balance is stable, but if the torque has to increase the body's rotation the balance is unstable

. When the body tends to rotate the torque with respect to the pivot point at the base it decreases because the distance from the center of gravity to the end of the base decreases in value, but it has to return it to the initial position, the balance is stable. The critical point of this process is when the center of gravity is at the limit of the body base area in this case the torque is zero; If the body rotates a little more the center of gravity is outside the base, the torque changes sign and has to increase the turn, going to an unstable balance.

In summary, when the center of gravity is within the washing area, the torque returns in the body to its initial position and is in a stable equilibrium.

8 0
3 years ago
Other questions:
  • When the distance between two interacting objects doubles, the gravitational force is
    11·1 answer
  • Which of the following tend to react by gaining 1 electron
    12·2 answers
  • What is the best inference for the height of the plant after 35 hours?
    15·1 answer
  • What should you do if your investigation does not support your hypothesis
    13·1 answer
  • Which sound characteristic is not affected by the relative motion of an object?
    9·2 answers
  • Options: Amplitude, crest, trough, wavelength
    13·1 answer
  • What is formula for time and velocity
    9·1 answer
  • A photoelectric-effect experiment finds a stopping potentialof 1.93V when light of 200nm is used to illuminate thecathode.
    8·1 answer
  • A toy car with a mass of 8 kg and velocity of 5 m/s to the right collides with a 5.28 kg car moving to the left with a velocity
    14·1 answer
  • For your answer to this problem, just type in the numerical magnitude of the momentum - no units.
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!