Answer:
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Explanation:
Answer:
6.54 × 10⁻⁵ Pa-s
Explanation:
Since the shear force, F = μAu/y where μ = viscosity of fluid between plates, A = area of plates, u = velocity of fluid = 0.6 m/s and y = separation of plates = 0.02 mm = 2 × 10⁻⁵ m
Since F = μAu/y
F/A = μu/y where F/A = force per unit area
Since we are given force per unit area, F/A = 1.962 N per unit area = 1.962 N/m²
So, μ = F/A ÷ u/y
substituting the values of the variables into the equation, we have
μ = F/A ÷ u/y
μ = 1.962 N/m² ÷ 0.6 m/s/2 × 10⁻⁵ m
μ = 1.962 N/m² ÷ 0.3 × 10⁵ /s
μ = 6.54 × 10⁻⁵ Ns/m²
μ = 6.54 × 10⁻⁵ Pa-s
the spring will be compressed by 0.3072 m
Explanation:
acceleration of elevator=3 m/s²
mass of student= 60 Kg
spring constant=2.5 x 10³ N/m
the force on the student is given by F = m ( g +a)
F=60 (9.8+3)
F=768 N
now the formula for spring force is given by
F= k x
768= 2.5 x 10³ (x)
x=0.3072 m
