For three moles of an ideal gas are taken around the eye, the total work for the cycle is mathematically given as
Wt=1945.475J
<h3>What is the total work F for the cycle.(R=8.31J/molK)?</h3>
Generally, the equation for work is mathematically given as
Wt=wac+Wc+Wba
Therefore
Wac=Pa(Vc-Va)=nR(Tc-Ta)
Wac=3(8.314*192)
Wac=4788.864J
Wcb=P1v1-p2v2/v-1
Wcb-3*8.34*108/0.4
Wcb=-6734.34J
Wab=0
In conclusion,
Wt=wac+Wc+Wba
Wt=4788.864J+0+(-6734.34J)
Wt=+1945.475J
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<u>Answer:</u>
Below!
<u>Explanation:</u>
Referring to the picture, we can conclude that the picture J will have the most effect on ocean tides.
Whichever model is similar to model J in the picture will be your answer.
Hoped this helped.
I'm pretty sure it's the neutron star.
5
If you go over 2 on the time bar, and you look for the black dot above the 2 on the bottom time bar, it would go up to 5.
