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allsm [11]
3 years ago
14

What happens to the beat when high tide comes in?

Chemistry
1 answer:
frez [133]3 years ago
7 0

If a high Crimson Tide player bumped into a Chicago Bear he would get whipped
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What is the hydrogen ion (H+) concentration of a solution of pH 8?
fgiga [73]

Answer:

10−8 M.

Explanation:

In this problem we are given pH and asked to solve for the hydrogen ion concentration. Using the equation, pH = − log [H+] , we can solve for [H+] as,

− pH = log [H+] ,

[H+] = 10−pH,

by exponentiating both sides with base 10 to "undo" the common logarithm. The hydrogen ion concentration of blood with pH 7.4 is,

[H+] = 10−7.4 ≈ 0.0000040 = 4.0 × In this problem we are given pH and asked to solve for the hydrogen ion concentration. Using the equation, pH = − log [H+] , we can solve for [H+] as,

− pH = log [H+] ,

[H+] = 10−pH,

by exponentiating both sides with base 10 to "undo" the common logarithm. The hydrogen ion concentration of blood with pH 7.4 is,

[H+] = 10−7.4 ≈ 0.0000040 = 4.0 × 10−8 M.

3 0
3 years ago
Read 2 more answers
When a parent has alleles for a dominant trait, what traits show up in the offspring?
Effectus [21]
Try putting this in biology category not chemistry so more ppl can help :)
4 0
3 years ago
What is the percentage yield of O2 if 12.3 g of KClO3 (molar mass 123 g) is decomposed to produce 3.2 g of O2 (molar mass 32 g)
My name is Ann [436]

Answer:

The percentage yield of O2 is 66.7%

Explanation:

Reaction for decomposition of potassium chlorate is:

2KClO₃ →  2KCl  +  3O₂

The products are potassium chloride and oxygen.

Let's find out the moles of chlorate.

Mass / Molar mass = Moles

12.3 g / 123 g/mol = 0.1 mol

So ratio is 2:3, 2 moles of chlorate produce 3 mol of oxygen.

Then, 0.1 mol of chlorate may produce (0.1  .3)/ 2 = 0.15 moles

Let's convert the moles of produced oxygen, as to find out the theoretical yield.

0.15 mol . 32 g/ 1mol = 4.8 g

To calculate the percentage yield, the formula is

(Produced Yield / Theoretical yield) . 100 =

(3.2g / 4.8g) . 100 = 66.7 %

8 0
3 years ago
Which of these methods could be used to separate an insoluble solid from a soluble solid? Melting the mixture and then using a f
I am Lyosha [343]

Answer : The correct option is "Mixing the mixture with water, filtering out the insoluble solid, and then evaporating the water to isolate the soluble solid.

Explanation :

"The given mixture contains a soluble solid and an insoluble solid.

When water is added to this mixture, the soluble solid will get dissolved in water whereas the insoluble solid will remain as it is.

This will give us a heterogeneous mixture where we can see 2 distinct phases , one containing the dissolved solid and the other having undissolved solid.

In order to separate these 2 phases, we can use a simple filtration method.

When the mixture is filtered, we will get solution having soluble solid and the insoluble solid will remain on the filter paper.

This will separate the 2 solids.

To regenerate the dissolved solid, we can evaporate the water by heating it. This will give us back our original soluble solid.

Therefore, the only option that is consistent with this method is "Mixing the mixture with water, filtering out the insoluble solid, and then evaporating the water to isolate the soluble solid"

8 0
3 years ago
One characteristic of a scientific theory is that ____.
faust18 [17]
It really base on facts ,hypotheses,evidences,concepts,
8 0
3 years ago
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