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zaharov [31]
2 years ago
15

A 14.8 L balloon is at 255 K. What will be its volume if the temperature is 304 K?

Chemistry
1 answer:
posledela2 years ago
3 0

Answer: 0.01764392156862745 L

(v1)/(t1)=(v2)/(t2)

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N2 (g) + 2O2(g) = 2NO2 (g) ΔH = 66.4 kJ 2NO (g) + O2 (g) = 2NO2 (g) ΔH = -114.2 kJ the enthalpy of the reaction of the nitrogen
RSB [31]

Answer:

ΔH  = 180.6 kJ

Explanation:

Given that:

N2 (g) + 2O2(g) = 2NO2 (g)           ΔH = 66.4 kJ

<u>2NO (g) + O2 (g) = 2NO2 (g)         ΔH = -114.2 kJ                     </u>

N2 (g) + O2 (g) = 2NO (g)              ΔH  = ????

The subtraction of both equations would yield the unknown ΔH , therefore:

ΔH = 66.4 - ( - 114.2 kJ)

ΔH  = 180.6 kJ

3 0
3 years ago
Read 2 more answers
Predict the formula for a compound made from X^2+ and Y^3-
slamgirl [31]
Compound is X3Y2.

Hope this helps you!
8 0
3 years ago
A form of carbon in which carbon atoms are arranged in a (n)__
abruzzese [7]

graphite is a form of carbon in which carbon atoms are arranged in a layer.

4 0
3 years ago
Select the correct structure that
Leto [7]

Answer:

c) both

Explanation:

hey, could you check the question once because I suppose it's 2-hexyne when there's a triple bond and 2-hexene when there's a double bond between Carbon atoms. As of the question asked, it's c) both but it's 2-hexene due to presence of double bond between Carbon atoms.

do tell me as well. have a good day :-))

6 0
2 years ago
Use electron configurations to account for the stability of the lanthanide ions Ce⁴⁺ and Eu²⁺.
Citrus2011 [14]

Answer:

Explanation:

 The Ce metal has electronic configuration as follows

[Xe] 4f¹5d¹6s²

After losing 4 electrons , it gains noble gas configuration ,. So Ce ⁺⁴ is stable.

Eu  has electronic configuration as follows

[ Xe ] 4 f ⁷6s²

[ Xe ] 4 f ⁷

Its outermost orbit contains 2 electrons so  Eu²⁺ is stable. Its +3 oxidation state is also stable.

Ce⁺²

7 0
3 years ago
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