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Dmitry [639]
3 years ago
5

The region bounded by the curve y = 2/(1 + e−x), the x- and y-axes, and the line x = 10 is rotated about the x-axis. Use Simpson

's Rule with n = 10 to estimate the volume of the resulting solid. (Round your answer to the nearest integer.
Mathematics
1 answer:
sp2606 [1]3 years ago
4 0

Answer:

21 darted to the nearest 10

Step-by-step explanation:

idk lol, sorry please don't report have great night or day where ever you live :D

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1/4 + 1/2 + x = - 3/4<br>solve for x​
e-lub [12.9K]

Answer:

X=-3/2

Step-by-step explanation:

1/4+1/2+X=-3/4

X=-3/4-1/4-1/2

X=-3/2

6 0
3 years ago
If a=8 and b=5 and x=4 and y=6m -2 what is the value of m ?
Serga [27]

Answer:

m = 2

Step-by-step explanation:

Given:

x = 4

y = 6m - 2

a = 8

b = 5

Required:

Value of m

SOLUTION:

x and y are segments of a chord divided when it intersects another chord that also has segments a and b.

According to the Intersecting chords theorem, a*b = x*y

Thus:

8*5 = 4*(6m - 2)

Solve for m

40 = 24m - 8

40 + 8 = 24m - 8 + 8

48 = 24m

\frac{48}{24} = \frac{24m}{24}

2 = m

The value of m = 2

3 0
3 years ago
Sharon wants to buy a shirt that costs $55. The sales tax is 5%. How much is the sales tax? What is her total cost for the shirt
Simora [160]
5% of $55 is $2.75 so the total should be $57.75??
7 0
2 years ago
The dual bar chart shows the hair colour of boys and girls in a year group. How many students are in the year group?
notka56 [123]

Answer:

102

Step-by-step explanation:

24+12+5+17+6+19+4+15=102

5 0
3 years ago
You are jumping off the 12 foot diving board at the municipal pool. You bounce up at 6 feet per second and drop to the water you
NARA [144]

Answer:

When do you hit the water?

1.075 seconds after you jump.

What is your maximum height?

the maximum height is 12.5626 ft

Step-by-step explanation:

The equation:

h(t) = -16*t^2 + 6*t + 12

Is the height as a function of time.

We know that the initial height is the height when t = 0s

h(0s) = 12

and we know that the diving board is 12 foot tall.

Then the zero in h(t)

h(t) = 0

Represents the surface of the water.

When do you hit the water?

Here we just need to find the value of t such that:

h(t) = 0 = -16*t^2 + 6*t + 12

Using the Bhaskara's formula, we get:

t = \frac{-6 \pm \sqrt{6^2 - 4*(-16)*12} }{2*(-16)} = \frac{-6 \pm 28.4}{-32}

Then we have two solutions, and we only care for the positive solution (because the negative time happens before the jump, so that solution can be discarded)

The positive solution is:

t = (-6 - 28.4)/-32 = 1.075

So you hit the water 1.075 seconds after you jump.

What is your maximum height?

The height equation is a quadratic equation with a negative leading coefficient, then the maximum of this parabola is at the vertex.

We know that the vertex of a general quadratic:

a*x^2 + b*x + c

is at

x = -b/2a

Then in the case of our equation:

h(t) = -16*t^2 + 6*t + 12

The vertex is at:

t = -6/(2*-16) = 6/32 = 0.1875

Evaluating the height equation in that time will give us the maximum height, which is:

h(0.1875) =  -16*(0.1875 )^2 + 6*(0.1875) + 12 = 12.5626

And the height is in feet, then the maximum height is 12.5626 ft

6 0
3 years ago
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