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2 years ago

Do you think an Electromagnet can be used for separating plastic bags from a garbage heap? explain

Physics

1 answer:

Alex73 [517]2 years ago

3 0

Answer:

Explanation:

Plastic bags are not magnetic materials, only magnetic materials (such as iron) can be attracted by the magnet.

Hope this helps.

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I think its A , it makes the most sense

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3 years ago

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So I know this is a weird question but if you were to send a piece of paper from the Milky Way to the andromeda galaxy how long

Mariana [72]

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Roughly 4.5 billion years

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3 years ago

How should the goals of a beginner differ from someone who is more advanced?

nevsk [136]

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A beginner is less skilled than someone who is more advanced, and has, in most cases, less experience.

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3 years ago

Two identical twins hold on to a rope, one at each end, on a smooth, frictionless ice surface. They skate in a circle about the

777dan777 [17]

Answer:

Part a)

$L = 2683.2 kg m^2/s$

Part b)

$v' = 8.60 m/s$

Part c)

$W = 4326.7 J$

Explanation:

Part a)

As we know that there is no external torque on the system of two twins

so here we will use

$L = mv r + mvr$

$L = 2(78 \times 4.30 \times 4)$

$L = 2683.2 kg m^2/s$

Part b)

Since angular momentum is conserved here as there is no external torque

so we will have

$2(m v r) = 2( m v' \frac{r}{2})$

$v' = 2v$

$v' = 8.60 m/s$

Part c)

Work done by both of them = change in kinetic energy

so we have

$W = 2(\frac{1}{2}mv'^2 - \frac{1}{2}mv^2)$

$W = m(v'^2 - v^2)$

$W = 78(8.60^2 - 4.3^2)$

$W = 4326.7 J$

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3 years ago

Suppose you charges parallel plate capacitor with a dielectric between the plates using a battery and the. Remove the bater, iso

Makovka662 [10]

Answer:

A) increase.

Explanation:

By definition, the capacitance of a capacitor, is the charge on one of the plates, divided by the potential difference between them, as follows:

$C = \frac{Q}{V} (1)$

At the same time, we can show (applying Gauss' Law to the surface of one of the plates), that the capacitance of a parallel-plate capacitor (with a dielectric of air), can be written as follows:

C = ε₀*A / d (2)

If the space between plates, is filled with a dielectric of dielectric constant κ, the above equation becomes:

$C =\frac{\epsilon_{0}*\kappa*A}{d} (3)$

If the capacitor, once charged, is disconnected from the battery, charge must keep the same.
Now, if we remove the dielectric, as stated in (3) and (2), the capacitance C will decrease when removing the dielectric.
From (1) if C decreases, and Q remains constant, in order to keep both sides of the equation equal each other, V (the potential difference between plates), must increase.

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3 years ago

Do you think an Electromagnet can be used for separating plastic bags from a garbage heap? explain​

Do you think an Electromagnet can be used for separating plastic bags from a garbage heap? explain