1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Elden [556K]
4 years ago
13

150kg object takes 1.5minutes to travel 2,500 meter straight path it begins the trip traveling 120m/s and decelerates to a veloc

ity of 20m/s whats its acceleration
Physics
1 answer:
Free_Kalibri [48]4 years ago
3 0
<h2>Answer:</h2>

Acceleration= -1.11 m/sec²


<h2>Explanation:</h2>

Date Given to us is

Mass = 150 kg

Time = 1.5 minutes = 90 seconds

Distance = 2500 meters

Initial Velocity = 120 m/s

Final Velocity = 20 m/s

Acceleration = ?

<u>Solution:</u>

By using First Equation of motion

Vf = Vi + at

Putting the values

20 = 120 + a (90)

Subtracting 120 on both sides

20-120 = 120 + a(90) - 120

-100 = 90 a

Dividing both sides by 90

-100/90 = 90 a / 90

-1.11 = a

So the acceleration is -1.11 m/s²

You might be interested in
A spherical shell rolls without sliding along the floor. The ratio of its rotational kinetic energy (about an axis through its c
True [87]

Answer:

The ratio  is  \frac{RE}{TE}  = \frac{2}{3}

Explanation:

Generally  the Moment of inertia of a spherical object (shell) is mathematically represented as

              I  =  \frac{2}{3} *  m r^2

Where m is  the mass of the spherical object

       and   r is the radius  

Now the the rotational kinetic energy can be mathematically represented as

       RE  = \frac{1}{2}*  I *   w^2

Where  w is the angular velocity which is mathematically represented as

             w =   \frac{v}{r}

=>           w^2  =   [\frac{v}{r}] ^2

So

             RE  = \frac{1}{2}*  [\frac{2}{3} *mr^2] *   [\frac{v}{r} ]^2

            RE  = \frac{1}{3} * mv^2

Generally the transnational  kinetic energy of this motion is  mathematically represented as

                TE = \frac{1}{2} mv^2

So  

      \frac{RE}{TE}  =  \frac{\frac{1}{3}  * mv^2}{\frac{1}{2} * m*v^2}

       \frac{RE}{TE}  = \frac{2}{3}

5 0
3 years ago
Jail
kykrilka [37]

Answer:

c.o Kg • ms 08

Explanation:

put all together

7 0
3 years ago
Which option is part of designing a set of experimental procedures?
zloy xaker [14]
B identifying the types of data to be gathered
4 0
3 years ago
Read 2 more answers
A negative test charge experiences a force to the right as a result of an electric field. Which is the best conclusion to draw
Alona [7]

Answer:a

Explanation:

4 0
3 years ago
Rules for competitive team sports set which limit?
Tanya [424]

Answer:

the skill level of players

Explanation:

5 0
3 years ago
Read 2 more answers
Other questions:
  • Most of the funding for research comes from the federal government or ? And is provided to Principal Investigators (PIs) through
    10·1 answer
  • A brick in the shape of a cube with sides 10 cm has a density of 2500 kg/m^3. What is its weight? a.) 250 N
    15·1 answer
  • a car company claims that its car can accelerate from rest to a speed of 28.0 m/s in 20.0 s. find the average acceleration of th
    14·1 answer
  • A proton (charge e), traveling perpendicular to a magneticfoeld, experiences the same force as an alpha particle (charge 2e)whic
    7·1 answer
  • Given that average speed is distance traveled divided by time, determine the values of m and n when the time it takes a beam of
    11·1 answer
  • A 260-m-wide river flows due east at a uniform speed of 4.1m's A boat with a speed of 7 5ms relative to the water leaves the sou
    12·1 answer
  • a closed tank is partially filled with glycerin. if the air pressure in the tank is 6 lb/in.2 and the depth of glycerin is 10 ft
    10·1 answer
  • Know the types of peer pressure describe all of them​
    6·1 answer
  • When in use, a lamp is designed to draw
    5·1 answer
  • What is a volume of a liquid in a 50ml cup
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!