A 2 kg and 2 meter long stick is held horizontally. A 4 kg mass is placed at 30 cm, and a 5 kg mass is placed at 75 cm. Determin
e the torque on the meterstick if it is received and allowed
1 answer:
Answer:
τ = 32.8635 N-m (counterclockwise)
Explanation:
Given
M = 2 kg
L = 2 m
r = 0.10 m
m₁ = 4 kg
r₁ = (1.00-0.30)m = 0.70 m
m₂ = 5 Kg
r₂ = (0.90-0.75)m = 0.15 m
In order to determine the torque on the meterstick if it is received and allowed to pivot about the 90 cm mark (ypu can see the pic to understand the question), we apply:
τ = r₁*m₁*g + r₂*m₂*g - r*M*g = g*(r₁*m₁+r₂*m₂-r*M)
⇒ τ = (9.81 m/s²)(0.70 m*4 kg + 0.15 m*5 Kg - 0.10 m*2 kg)
⇒ τ = 32.8635 N-m (counterclockwise)
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Answer:
The Temperature is the measure of Average Kinetic Energy of the molecule in the substance.
Temperature and Kinetic Energy of molecules are related by the equation
Where
<E> denotes average kinetic energy
k - Boltzmann constant
T - Temperature of the substance
Explanation:
The energy inside the substance is characterised by translational and vibrational motion.
The molecules in a substance have a range of kinetic energies because they don't all move at the same speed. As a substance absorbs heat the particles move faster so the average kinetic energy and therefore the temperature increases.
As the molecules of a substance vibrate faster their temperature increases.
Thus an increase energy corresponds to an increase in temperature
<E> α T (α denotes proportionality)