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Gemiola [76]
2 years ago
14

How u do this atomic mass

Physics
2 answers:
bezimeni [28]2 years ago
6 0
Vas happenin!!


To find atomic mass you you add the protons and the neutrons


Hydrogen-
Atomic number: 1
Atomic mass: 1.008
Number of protons: 1
Number of electrons: 1
Number of neutrons: 1



Helium-
Atomic number: 2
Atomic mass: 4.0026
Number of protons: 2
Number of neutrons: 2
Number of electrons: 2


Hope this helps

-Zayn Malik
Eddi Din [679]2 years ago
5 0

Explanation:

Hydrogen

Atomic Number=1

Atomic Mass= 1

number of protons= 1

number of electrons= 1

number of neutrons= 0

Helium

atomic number=2

atomic mass=2

number of protons=2

number of electrons=2

number of neutrons=2

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In a simple machine, the energy input is 120 J. If the efficiency of the machine is 80%, calculate the energy output
pashok25 [27]

Answer:

<h2>96 Joules</h2>

Explanation:

We know that efficiency is the ratio of output power by input power. i.e. Efficiency describes the quality of machine or system how good it is.

Solution,

Energy input of system = 120 J

Efficiency = 80% = \frac{80}{100}  = 0.8

Now,

According to definition,

Efficiency = \frac{output}{input}

Cross multiplication:

output \:  =  \: 0.8 \times 120

Calculate the product

output \:  = 96 \: joules

Hope this helps...

Good luck on your assignment...

4 0
3 years ago
A scientist carries out an experiment. How could she help other scientists judge the validity of her results?
NNADVOKAT [17]
One way to do it is she could right down the data that she got
4 0
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A body has masses of 0.013kg and 0.012kg in oil and water respectively, if the relative density of oil is 0.875, calculate the m
konstantin123 [22]

Answer:

the mass of the body is 0.02 kg.

Explanation:

Given;

relative density of the oil, \gamma _0 = 0.875

mass of the object in oil, M_o = 0.013 kg

mass of the object in water, M_w = 0.012 kg

let the mass of the object in air = M_a

weight of the oil, W_0 = M_a - 0.013

weight of the water, W_w = M_a - 0.012

The relative density of the oil is given as;

\gamma_0 = \frac{density \ of \ oil }{density \ of \ water} = \frac{W_0}{W_w} = \frac{M_a -0.013}{M_a -0.012} \\\\0.875 = \frac{M_a -0.013}{M_a -0.012}\\\\0.875(M_a - 0.012) = M_a - 0.013\\\\0.875M_a - 0.0105 = M_a -0.013\\\\0.875M_a - M_a = 0.0105 - 0.013\\\\-0.125 M_a = -0.0025\\\\M_a = \frac{0.0025}{0.125} \\\\M_a = 0.02 \ kg

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6 0
2 years ago
The results of a recent television survey of American TV households revealed that 86 out of every 100 TV households have at leas
Lelechka [254]

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q = \dfrac{14}{100}

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given,

86 out of every 100 TV households have at least one remote control

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P(at\ least\ one\ remote\ control)=\dfrac{86}{100}

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now, Calculating probability that at least one remote control

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