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3 years ago

How u do this atomic mass

Physics

2 answers:

bezimeni [28]3 years ago

6 0

Vas happenin!!

To find atomic mass you you add the protons and the neutrons

Hydrogen-
Atomic number: 1
Atomic mass: 1.008
Number of protons: 1
Number of electrons: 1
Number of neutrons: 1

Helium-
Atomic number: 2
Atomic mass: 4.0026
Number of protons: 2
Number of neutrons: 2
Number of electrons: 2

Hope this helps

-Zayn Malik

Eddi Din [679]3 years ago

5 0

Explanation:

Hydrogen

Atomic Number=1

Atomic Mass= 1

number of protons= 1

number of electrons= 1

number of neutrons= 0

Helium

atomic number=2

atomic mass=2

number of protons=2

number of electrons=2

number of neutrons=2

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2 years ago

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$V_{2} = \frac{0.72 - 0.3 V_{1}}{0.8}$ ..................(2)

Using the law of conservation of kinetic energy:

$0.5m_{1} u_{1} ^{2} + 1.2 = 0.5m_{1} V_{1} ^{2} + 0.5m_{2} V_{2} ^{2}\\0.5(0.3) (2.4) ^{2} + 1.2 = 0.5(0.3) V_{1} ^{2} + 0.5(0.8)V_{2} ^{2}\\$

$2.064 = 0.15 V_{1} ^{2} + 0.4V_{2} ^{2}$ .......(3)

Substitute equation (2) into equation (3)

$2.064 = 0.15 V_{1} ^{2} + 0.4(\frac{0.72 - 0.3V_{1} }{0.8}) ^{2}\\2.064 = 0.15 V_{1} ^{2} + 0.4(\frac{0.5184 - 0.432V_{1} + 0.09V_{1} ^{2} }{0.64}) \\1.32096 = 0.096 V_{1} ^{2} + 0.20736 - 0.1728V_{1} + 0.036V_{1} ^{2} \\0.132 V_{1} ^{2} - 0.1728V_{1} - 1.1136 = 0\\V_{1} = 3.632 m/s$

Substituting $V_{1}$ into equation(2)

$V_{2} = \frac{0.72 - 0.3 *3.632}{0.8}\\V_{2} = \frac{0.72 - 0.3 *(3.632)}{0.8}\\V_{2} = 0.462 m/s$

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3 years ago