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scoray [572]
3 years ago
8

An electric field of 1139 V/m is applied to a section of silver of uniform cross section. Find the resulting current density if

the specimen is at a temperature of 3 ◦C . The resistivity ρ of silver is 1.59 × 10−8 Ω · m at 20 ◦C . and its temperature coefficient is 0.0038 (◦C)−1 . Answer in units of A/m
Physics
1 answer:
N76 [4]3 years ago
8 0

Answer:

So, you're going to need the equation ρ = ρo [1 + α(T-To)]  

1.59x10^-8 ohms*m is your ρo because that is measured at your reference temperature (To), 20◦C. T is your 6◦C and α is 0.0038(◦C)−1. So, using that you solve for ρ. If you keep up with the units though, you notice it comes out to be ohms*m and that isn't what you want.  

So, the next equation you need is J=σE where E is your electric field (3026 V/m) and σ is the electrical conductivity which is the inverse of your answer you got in the previous equation. So find the inverse of that answer and multiply it by your electric field and that will give you the current density.  

I hope this helps!

Explanation:

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2 years ago
A device called an insolation meter is used to measure the intensity of sunlight. It has an area of 100 cm2 and registers 6.50 W
labwork [276]

Answer:

<h2>650W/m²</h2>

Explanation:

Intensity of the sunlight is expressed as I  = Power/cross sectional area. It is measured in W/m²

Given parameters

Power rating = 6.50Watts

Cross sectional area = 100cm²

Before we calculate the intensity, we need to convert the area to m² first.

100cm² = 10cm * 10cm

SInce 100cm = 1m

10cm = (10/100)m

10cm = 0.1m

100cm² = 0.1m * 0.1m = 0.01m²

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Required

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I = 6.5/0.01

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Hence, the intensity of the sunlight in W/m² is 650W/m²

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Answer:

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So the correct ans is B.

hope it helps u.

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