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miss Akunina [59]
2 years ago
13

What is the purpose of this block?

Engineering
1 answer:
just olya [345]2 years ago
3 0

The  purpose of a block to add a value to the end of an array.

<h3>What is the function that adds an element to the end of an array?</h3>

The push() is known to be often used to add an element to the end of your array.

The end() function is known to be one that transmit the internal pointer to, and also the outputs, the last factor in the array.

A null or zero value is known to be that which marks the end of an array and it is said to be the very equivalent of the null char for any kind of string

Hence, in the above scenario, The  purpose of a block to add a value to the end of an array.

Therefore, option D is correct.

Learn more about  array from

brainly.com/question/24275089

#SPJ1

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Which size of impurity atom, smaller impurity atom or larger impurity atom, when located near a dislocation, will nullify some o
svp [43]

Answer:

Smaller impurity atom will nullify some of the compressive strain of a dislocation in a crystal. Because, smaller impurity atoms located near a dislocation creates tensile strain on atoms around it thereby partially nullifying compressive strain at the dislocation.

4 0
3 years ago
Which of the following describes the most direct and attainable way to reduce pollution in the environment?
kirill115 [55]

Answer:

i think its A. increasing research to find alternative natural resources for the future

5 0
3 years ago
Read 2 more answers
Write in an Excel cell the appropriate @RISK function for a binomial distribution that results from 50 trials with probability o
borishaifa [10]

Answer:

Binomial Function

I got my output using the formula = 1 - BINOMDIST (17, 50, 0.3, TRUE)

Then got the cumulative probability distribution at 17 to be 0.2178

Explanation:

To draw a normal distribution:

1. Got to '@risk' and click on 'defined distribution'

2. Select 'binomial' in function block

3. enter formula in cell formula and click okay

The use of @RISK to draw a binomial distribution of 50 trials and probability of success as 0.3 by entering formular =RISKBINOMIAL (50, 0.3).

6 0
3 years ago
The torque required to drive a 40 mm diameter power screw having double square threads with a pitch of 6 mm is 1.0 kN-m. The fri
myrzilka [38]

Answer:

This is self locking.

Explanation:

Given that

Diameter d= 40 mm

Pitch (P)= 6 mm

Torque T= 1 KN.m

Friction(μ) = 0.1

Thread is double square.

Condition for self locking

\mu >tan\theta

tan\theta=\dfrac{L} {\pi d}

L= n x P

N= number of start

Here given that double start so n=2

L=2 x 6 = 12 mm

tan\theta=\dfrac{L} {\pi d}

tan\theta=\dfrac{12} {\pi \times 40}

tan\theta=0.095            (μ = 0.1)

\mu >tan\theta

So from we can that this is self locking.

6 0
3 years ago
Select the correct answer.
andre [41]

Answer:

A. energy transformations

Explanation:

8 0
2 years ago
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