Answer:
Explanation:
Two previously undeformed cylindrical specimens of an alloy are to be strain hardened by reducing their cross-sectional areas (while maintaining their circular cross sections). For one specimen, the initial and deformed radii are 15 mm and 12 mm, respectively. The second specimen, with an initial radius of 11 mm, must have the same deformed hardness as the first specimen.Compute the second specimen's radius after deformation.
The percentage of cold work to be done to deform the two cylindrical is calculated
we input the values
We can now calculate the deformed radius of the second specimen for the same deformation
Answer:
f(x) = x -3
Explanation:
Solve for y, then replace y by f(x).
x - y = 3
x - 3 = y . . . . . add y-3 to both sides
f(x) = x -3
Answer:
The volumetric flow rate through the slot is 0.05472 m^3/s
Explanation:
Volumetric flow rate = peak velocity × slot width × slot height
Peak velocity = 0.8 m/s
Slot width = 114 mm = 114/1000 = 0.114 m
Slot height = 0.6 m
Volumetric flow rate = 0.8 m/s × 0.114 m × 0.6 m = 0.05472 m^3/s
Answer:
Look at some engineering colleges and set up or join a public zoom meeting. For example, some colleges have sign ups for zoom calls on set dates and you‘re able to ask questions.
Explanation: