Answer:
(-x +5) -5/(3x)
Step-by-step explanation:
Divide term by term.
= (3x^2)/(-3x) +(-15x)/(-3x) +(5)/(-3x)
= -x +5 -5/(3x)
X^2+6^2=10^2
X^2+36=100
Subtract 36 from both sides
X^2= 64
X=8
Answer:
The ordered pair
make both inequalities true
Step-by-step explanation:
we have
------> inequality A
------> inequality B
we know that
If a ordered pair satisfy both inequalities
then
the ordered pair is a solution of both inequalities
we're going to verify every case
<u>case A)</u> point ![(1,0)](https://tex.z-dn.net/?f=%281%2C0%29)
Substitute the values of x and y in both inequalities
![x=1, y=0](https://tex.z-dn.net/?f=x%3D1%2C%20y%3D0)
<u>Inequality A</u>
![y](https://tex.z-dn.net/?f=y%20%3C-3x%2B3)
![0](https://tex.z-dn.net/?f=0%20%3C-3%2A1%2B3)
------> is not true
therefore
The ordered pair
does not make both inequalities true
It's not necessary to verify the B inequality
<u>case B)</u> point ![(-1,1)](https://tex.z-dn.net/?f=%28-1%2C1%29)
Substitute the values of x and y in both inequalities
![x=-1, y=1](https://tex.z-dn.net/?f=x%3D-1%2C%20y%3D1)
<u>Inequality A</u>
![y](https://tex.z-dn.net/?f=y%20%3C-3x%2B3)
![1](https://tex.z-dn.net/?f=1%20%3C-3%2A%28-1%29%2B3)
------> is true
<u>Inequality B</u>
------> is true
therefore
The ordered pair
make both inequalities true
<u>case C)</u> point ![(2,2)](https://tex.z-dn.net/?f=%282%2C2%29)
Substitute the values of x and y in both inequalities
![x=2, y=2](https://tex.z-dn.net/?f=x%3D2%2C%20y%3D2)
<u>Inequality A</u>
![y](https://tex.z-dn.net/?f=y%20%3C-3x%2B3)
![2](https://tex.z-dn.net/?f=2%20%3C-3%2A%282%29%2B3)
------> is not true
therefore
The ordered pair
does not make both inequalities true
It's not necessary to verify the B inequality
<u>case D)</u> point ![(0,3)](https://tex.z-dn.net/?f=%280%2C3%29)
Substitute the values of x and y in both inequalities
![x=0, y=3](https://tex.z-dn.net/?f=x%3D0%2C%20y%3D3)
<u>Inequality A</u>
![y](https://tex.z-dn.net/?f=y%20%3C-3x%2B3)
![3](https://tex.z-dn.net/?f=3%20%3C-3%2A%280%29%2B3)
------> is not true
therefore
The ordered pair
does not make both inequalities true
It's not necessary to verify the B inequality
We need to find the probability of picked out each color. The are 4 red, 7 white, and 3 blue marbles. There are 14 marbles total.
So there are 4 red marbles out of the 14 marbles total. As fraction it is
which simplifies to
. To convert to a decimal, divide 2 by 7 to get about 0.2857. To convert a decimal to a percent, move the decimal point 2 spaces down to get 28.57%
There are 7 white marbles out of 14 marbles total. As fraction it is
which simplifies to
. This is 0.5 or 50%.
There are 3 blue marbles out of 14 marbles total. As fraction it is
which can't simplify. Divide 3 by 14 to get the decimal which is about 0.2143. Move the decimal 2 spaces down (basically dividing it by 100) to get 21.43%.
Answer:
2 CH4(g) + 4 O2(g) --> 2 CO2 (g)+ 4 H2O(g)
Step-by-step explanation:
The number are subscripts.
Now count the number of each kind of atom on the left and right side of the equation. Note, you have 4 H on the left and as written you have only 2 on the right. So add a coefficient-- a number in front of the formula.
CH4 +O2 ----- CO2 + 2 H2O
With the added coefficient in front of water, the number of hydrogens balance but the number of oxygens do not. There are only 2 oxygens on the left and a total of 4 oxygens on the right. A coefficient of 2 in front of oxygen on the left balances the equation.