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Svetach [21]
2 years ago
5

Which would require the greater energy; slowing down of the orbital speed of the Earth so it crashes into the sun, or speeding u

p the orbital speed of the Earth so it escapes the sun
Physics
1 answer:
tresset_1 [31]2 years ago
3 0

Answer: Speeding up the orbital speed of earth so it escapes the sun require the greater energy.

Explanation: To find the answer, we need to know more about the Orbital and escape velocities.

<h3>What is Orbital and Escape velocity?</h3>
  • Orbital velocity can be defined as the minimum velocity required to put the satellite in its orbit around the earth.
  • The expression for orbital velocity near to the surface of earth will be,

                   V_o=\sqrt{gR}

  • Escape velocity can be defined as the minimum velocity with which a body must be projected from the surface of earth, so that it escapes from the gravitational field of earth.
  • The expression for orbital velocity will be,

                    V_e=\sqrt{2gR}

  • If we want to get into the sun, we want to slow down almost completely, so that your speed relative to the sun became almost zero.
  • We need about twice the raw speed to go to the sun than to leave the sun.

Thus, we can conclude that, the speeding up the orbital speed of earth so it escapes the sun require the greater energy.

Learn more about orbital and escape velocity here:

brainly.com/question/28045208

#SPJ4

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Answer:

A

Explanation:

Actual output divided by the effective capacity. It is the ratio of output to effectiveness

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The exact speed of an object in a specific instant is?
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You drop your frozen rock from a green bridge. The frozen rock starts from rest (initial velocity = 0ms). The rock takes 4.3s to
valentinak56 [21]

Answer:

The velocity of the frozen rock at t = 1.5\,s is -14.711 meters per second.

Explanation:

The frozen rock experiments a free fall, which is a type of uniform accelerated motion due to gravity and air viscosity and earth's rotation effect are neglected. In this case, we need to find the final velocity (v), measured in meters per second, of the frozen rock at given instant and whose kinematic formula is:

v = v_{o} + g\cdot t (Eq. 1)

Where:

v_{o} - Initial velocity, measured in meters per second.

g - Gravity acceleration, measured in meters per square second.

t - Time, measured in seconds.

If we get that v_{o} = 0\,\frac{m}{s}, g = -9.807\,\frac{m}{s^{2}} and 1.5\,s, then final velocity is:

v = 0\,\frac{m}{s}+\left(-9.807\,\frac{m}{s^{2}} \right) \cdot (1.5\,s)

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The velocity of the frozen rock at t = 1.5\,s is -14.711 meters per second.

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