ILL GIVE BRAINLIST PLS In which circuit does charge reverse direction many times per second?
1 answer:
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Answer:
B. Ball B will take longer to complete one cycle
Explanation:
This is simply because the period of a simple pendulum is affected by acceleration due to gravity, while the period of an ideal spring is not.
This can be clearly deduced by observing the formulas for the various systems.
Formula for period of simple pendulum:
T = 2π ×
Formula for period of an oscillating spring:
T= 2π ×
The period of the simple pendulum is affected by the length of the string and the acceleration due to gravity as shown above. Thus, it will have a different period as the gravitational acceleration changes on the moon. Thus will be a larger period <em>(slower oscillation) </em>as the gravitational acceleration is smaller in this case
The period of the oscillating spring is only affected by the mass of the load an the spring constant as shown above. Thus, it will have a period similar to the one it had on the earth because the mass of the ball did not change as the setup was taken to the moon.
All these will make the ball on the spring (Ball B) oscillate faster than the ball swinging on the string (Ball A)
Answer:
vf = 22.36[m/s]
Explanation:
First we must understand the data given in the problem:
m = mass = 800 [kg]
F = force = 20000[N]
dx = displacement = 10[m]
From newton's second we know that the sum of forces must be equal to the product of mass by acceleration.
With the calculated acceleration, we can use the kinematics equations.
The key to using this equation is to clarify that the initial velocity is zero since the body is at rest, otherwise the initial velocity would be an initial data.
Another way of solving this problem is by means of the definition of work and kinetic energy, where work is defined as the product of the force by the distance.
W =F*d
W = 20000*10
W = 200000[J]
Kinetic energy is equal to work, therefore the value calculated above is equal to: