<span>Physicists use certain units to measure heat energy and electrical energy:
- Joule (Watt sec )
- Watt - hour
- Kilowatt- hour
- Calorie
Hope this helps!
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Answer:
I =
(K+5)
Explanation:
Given :
J = k+5
Now selecting a thin ring in the wire of radius "r" and thickness dr.
Current through the thin ring is
dI = J X 2πrdr
dI = (K+5) x 2πrdr
Now integrating we get
I = 
I = (K+5) 2π
I = (K+5) 2π 
I =
(K+5)
D. Microwaves use radiation, hence the “wave” in microwave