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3 years ago

The two days of the year on which neither hemisphere is tilted toward or away from the sun are called

Physics

2 answers:

Dmitry_Shevchenko [17]3 years ago

5 0

The solstice,they are of two types winter and summer

Serggg [28]3 years ago

3 0

Answer:

Solstices

Explanation:

The solstices are the days of the year in which the sun reaches its highest or lowest apparent height in the sky, and the duration of the day or night is the maximum of the year, respectively. The summer solstice of the northern hemisphere occurs between June 20 and 22 and between December 20 and 22 of each year the winter solstice of the northern hemisphere occurs

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When two point charges are a distance dd part, the electric force that each one feels from the other has magnitude F.F . In orde

Harman [31]

Answer:

In order to make this force twice as strong, F' = 2 F, the distance would have to be changed to half i.e. r' = r/2.

Explanation :

The electric force between two point charges is directly proportional to the product of charges and inversely proportional to the square of the distance between charges. It is given by :

$F=\dfrac{kq_1q_2}{r^2}$

r is the separation between charges

$F\propto \dfrac{1}{r^2}$

$r=\sqrt{\dfrac{1}{F}}$

If F'= 2F

$r'=\dfrac{1}{\sqrt{2F} }$

In order to make this force twice as strong, F' = 2 F, the distance would have to be changed to half i.e. $r'=\dfrac{1}{\sqrt{2F} }$ . Hence, this is the required solution.

6 0

3 years ago

A ramp is used to lift a refrigerator a height of 12 m with a force of 110 N. The ramp is at an angle of 50° to the ground.How m

nikitadnepr [17]

Answer:

848.5 J

Explanation:

We are given that

Height,h=12 m

Force,F=110 N

$\theta=50^{\circ}$

We have to find the work done .

We know that

Work done,W= $Fscos\theta$

Using the formula

W= $110\times 12cos50$

W=848.5 J

Hence,the work done=848.5 J

8 0

3 years ago

Joe follows the procedure below to make a compass.

Anna [14]

The answer would be C.

8 0

3 years ago

Read 2 more answers

You are standing a distance of 17.0 meters from the center of a merry-go-round. The merry-go-round takes 9.50 seconds to go comp

GenaCL600 [577]

Answer:

(a)11.24 m/s

(b)7.44 m/s

(d) $539.55\mu$

(e) 0

Explanation:

The period for 1 circle $2\pi$ of the merry go around is 9.5s. It means the angular speed is:

$\omega = \theta / t = 2\pi / 9.5 \approx 0.661 rad/s$

(a)The speed is

$v = \omega * R = 0.661 * 17 = 11.24 m/s$

(b) Centripetal acceleration:

$a = \frac{v^2}{R} = \frac{11.24^2}{17} = 7.44 m/s^2$

$F = ma = 55 * 7.44 = 409 N$

(d) let the coefficient of friction by $\mu$ . The frictional force shall be this coefficient multiplied by normal force reverting gravity of the man

$F_f = mg\mu = 55*9.81\mu = 539.55\mu$

3 0

3 years ago

PLEASE HELP!! At what temperature will silver have a resistivity that is four times the resistivity of tungsten at room temperat

Svetach [21]

Consider 20 deg.C. as room temperature.

From tables,
Silver has a resistivity of 1.6*10^-8 ohm-m at 20 deg.C, and it increases by 0.0038 ohm-m per deg.K increase.
Therefore if the temperature rise above 20 deg.C is T, then silver will have resistivity of
1.6*10^-8(1 + 0.0038T) ohm-m

At room temperature, the resistivity of tungsten (from tables) is 5.6*10^-8.

The resistivity of silver will be 4 times that of tungsten (at room temperature) when
1.6*10^-8(1 + 0.0038T) = 4*5.6*10^-8
1 + 0.0038T = 14
T = 13/.0038 = 3421 deg.K approx

Answer: 20 + 3421 = 3441 °C

4 0

3 years ago