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sasho [114]
3 years ago
12

How long does it take light to travel 850 km in a vacuum? Answer in ms.(Express your answer to two significant figures.)

Physics
1 answer:
poizon [28]3 years ago
5 0

Answer:

0.002833 sec

Explanation:

Speed of light in vacuum is 3\times 10^{8}m/sec

Given distance = 850 km = 850×1000=850000 m

We have to calculate the time that light take to travel the distance 850 km

Time T=\frac{distance }{speed}=\frac{850000}{3\times 10^8}=2.833\times 10^{-3}sec

So the time taken by light to travel 850 km is 0.002833 sec

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With a 30 mph head wind it takes the plane 18.52 hours to fly 5000 miles. ANSWER 2: With a 30 mph tail wind it takes the plane 15.15 hours to fly 5000 miles.
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Which term describes a long-term weather pattern?<br> air mass<br> climate<br> humidity<br> front
Leni [432]

Answer:

Explanation:

The answer is Climate

4 0
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Read 2 more answers
Consider an alien on a planet with an acceleration of gravity equal to 20 m/sec^2. If the alien's mass is 10 kg, how much does t
mr_godi [17]

Answer:

the weight of alien is 200 newtons

Explanation:

The computation of the alien weight is shown below:

Given that

Acceleration = 20m/sec^2

And, the mass is 10 kg

So, the weight of alien is

= 20 × 10

= 200 newtons

hence, the weight of alien is 200 newtons

6 0
3 years ago
Need help asap please and thank you​
nordsb [41]
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distance = 116 x 10

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6 0
3 years ago
A circular loop with radius r is rotating with constant angular velocity ω in a uniform electric field with magnitude E. The axi
inn [45]

Answer:

\Phi_{E} = E\pi r^2 \omega t

Explanation:

The electric flux is defined as the multiple of electric field and the area that the electric field passes through, such that

\Phi_{E} = \vec{E}\vec{A}

When calculating the electric flux, the angle between the directions of electric field and the area becomes important, especially if the angle is changing with time.

The above formula can be rewritten as follows

\Phi_{E} = EA\cos(\theta)

where θ is the angle between the electric field and the area of the loop. Note that, the direction of the area of the loop is perpendicular to the plane of the loop.

If the loop is rotating with constant angular velocity ω, then the angle can be written as follows

\theta = \omega t

At t = 0, cos(0) = 1 and the electric flux through the loop is at its maximum value.

Therefore the electric flux can be written as a function of time

\Phi_{E} = E\pi r^2 \omega t

3 0
3 years ago
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