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BigorU [14]
3 years ago
15

What is 178.57 rounded to the nearest whole number

Physics
2 answers:
Black_prince [1.1K]3 years ago
8 0

Answer:179

Explanation:

You round up when the number behind the decimal is 5 or greater and down when less than 5

postnew [5]3 years ago
4 0
<h2><em>178.57</em></h2>

<h2><em>=</em><em> </em><em>178</em><em>.</em><em>6</em></h2>

<h2><em>=</em><em> </em><em>179</em></h2>

<h2><em>THANK</em><em> </em><em>YOU</em><em> </em></h2>
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Mark creates a graphic organizer to review his notes about electrical force. Which labels belong in the regions marked X and Y?
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The question requires as well the attached image, so please see that below.

Coulomb's Law.

The electrical force can be understood by remembering Coulomb's Law, that  describes the electrostatic force between two charged particles. If the particles have charges q_1 and q_2, are separated by a distance r and are at rest relative to each other, then its electrostatic force magnitude on particle 1 due particle 2 is given by:

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Thus if we decrease the distance by half we have

r_1 =\cfrac r2

So we get

|F|=k \cfrac{q_1 q_2}{r_1^2}

Replacing we get

|F|=k \cfrac{q_1 q_2}{(r/2)^2}\\|F|=k \cfrac{q_1 q_2}{r^2/4}

We can then multiply both numerator and denominator by 4 to get

|F|=k \cfrac{4q_1 q_2}{r^2}

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|F|=4 \left(k \cfrac{q_1 q_2}{r^2}\right)

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Then we can replace the second condition

q_{2new} =2q_2

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|F|=k \cfrac{q_1 q_{2new}}{r_1^2}

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|F|=k \cfrac{q_1 2q_2}{r_1^2}\\|F|=2\left(k \cfrac{q_1 q_2}{r_1^2}\right)

Thus doubling one of the charges doubles the force.

So the answer is A.

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