Answer:
Ground state electronic configuration of oxygen atom is as follows - is 1s2 2s2 2p2x 2p1y 2p1z 1s2 2s2 2px2 2py1 2pz1
Ground state electronic configuration of hydrogen atom is 1s1 1s1
Explanation:
As per the Valence Bond Theory (VBT),
Ground state electronic configuration of oxygen atom is as follows - is 1s2 2s2 2p2x 2p1y 2p1z 1s2 2s2 2px2 2py1 2pz1
Ground state electronic configuration of hydrogen atom is 1s1 1s1
Considering the electronic configuration, H-O-H bond angle would be at 90 degrees as 2py2py and 2pz2pz are oriented 90° with respect to each other. But if the oxygen atomic orbitals is used directly then bond angle for water is 104.45° as per the VSEPR theory which states that 2s2s spherical orbit in oxygen can adjust the bond angle by creating new hybrid orbitals
Answer:
273 K
Explanation:
The temperature of a gas at STP is 273 K. This is equal to 0°C or 32°F.
The answer is 267.93 g
Molar mass of CaBr2 is the sum of atomic masses of Ca and Br:
Mr(CaBr2) = Ar(Ca) + 2Ar(Br)
Ar(Ca) = 40 g/mol
Ar(Br) = 79.9 g/mol
Mr(CaBr2) = 40 + 2 * 79.9 = 199.8 g/mol
The percentage of Br in CaBr2 is:
2Ar(Br) / Mr(CaBr2) * 100 = 2 * 79.9 / 199.8 * 100 = 79.98%
Now make a proportion:
x g in 79.98%
335 g in 100%
x : 79.98% = 335 g : 100%
x = 79.98% * 335 g : 100%
x = 267.93 g
Cl⁻ + H₂O(g) = HCl(g) + OH⁻
w - it is percent chloride ions in solid sea salt (as a rule 55%)
m - it is the mass of sea salt
m(Cl⁻)=mw/100
m(Cl⁻)/M(Cl)=V(HCl)/V₀
mw/{100M(Cl)}=V(HCl)/V₀
m=100M(Cl)V(HCl)/{wV₀} (<span>the mass of solid sea salt)</span>
V₀=22.4 L/mol
M(Cl)=35.45 g/mol
for example:
V(HCl)= 1.0 L
w=55%
m=100×35.45×1.0/{55×22.4}=2.88 g
Answer:
M = 1 M
Explanation:
Given data:
Mass in gram = 342.2 g
Volume of solution = 1.0 L
Molar concentration = ?
Solution:
Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.
Formula:
Molarity = number of moles of solute / L of solution
Number of moles of sucrose:
Number of moles = mass/molar mass
Number of moles = 342.2 g/ 342.2 g/mol
Number of moles = 1 mol
Molarity:
M = 1 mol / 1.0 L
M = 1 mol/L
M = 1 M