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3 years ago

Which molecular compound is composed of the greatest number of atoms?

Chemistry

1 answer:

nlexa [21]3 years ago

5 0

Answer:

Answer:

Potassium Nitride is composed of the greatest number of atoms.

Explanation:

find the number of atoms present in each compound we will write down their molecular formulas and then we will add up the number of atoms present in them.

A: Dinitrogen Monoxide:

Chemical formula of Dinitrogen Monoxide is N₂O. Therefore, it contains two atoms of Nitrogen and one atom of oxygen Hence, in total it contains 3 atoms.

B: Sodium Chloride:

Chemical formula of Sodium Chloride is NaCl. Therefore, it contains one atom of Sodium and one atom of Chlorine Hence, in total it contains 2 atoms.

C: Potassium Nitride:

Chemical formula of Dinitrogen Monoxide is K₃N. Therefore, it contains three atoms of Potassium and one atom of Nitrogen Hence, in total it contains 4 atoms.

D: Carbon Dioxide:

Chemical formula of Carbon Dioxide is CO₂. Therefore, it contains one atom of Carbon and two atoms of Oxygen Hence, in total it contains 3 atoms.

Explanation:

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A solid piece of aluminum (51.0 g) was added to a solution of sodium hydroxide (84.1 g) in water, A balanced equation for this r

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$M_{Al}=26,98\frac{g}{mol}\\
m=51g\\\\
n=\frac{m}{M_{Al}}=\frac{51g}{26,97\frac{g}{mol}}\approx1,89mol\\\\\\
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m=84,1g\\\\
n=\frac{m}{M_{NaOH}}=\frac{84,1g}{39,4\frac{g}{mol}}\approx2,14mol$

2 NaOH(aq)+ 2 Al(s)+ 2 H₂O → 2 NaAlO₂(aq)+ 3 H₂(g)
 2mol : 2mol : 3mol
2,14mol : 1,89mol : 2,835mol
remains completely consumed
2,14-1,89=0,25mol

A) Al

B)

$M_{NaOH}=39,4\frac{g}{mol}\\
n=0,25mol \Rightarrow \ \ \ m=n*M_{NaOH}=0,25mol*39,4\frac{g}{mol}=9,85g$

C)
$n=2,835mol\\
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