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VashaNatasha [74]
4 years ago
6

What is the precipitate that will form from the reaction of barium chloride dihydrate with sodium sulfate decahydrate?

Chemistry
2 answers:
iragen [17]4 years ago
4 0
 <span>immediate milky appearance 
after 5-10 minutes a precipitate of BaSO4 will settle out of solution the the solution will be clear.
</span>but mostly a white precipitate

MakcuM [25]4 years ago
4 0

The formation of an insoluble salt on mixing of two solutions which contains soluble salts is refer to a precipitation reaction. The insoluble salt formed in the reaction is said to be a precipitate and can be separated by filtration or any other separation method.

The formula for barium chloride dihydrate is BaCl_2.2H_2O.

The formula for sodium sulfate decahydrate is Na_2SO_4.10H_2O.

The hydrates on the above compounds represents that they are in the aqueous phase. So, the reaction is:

BaCl_2(aq) + Na_2SO_4(aq) \rightarrow BaSO_4(s) + NaCl(aq)

The above equation is not balanced as the number of atoms of elements on the reactant side is not equal to the number of atoms of elements on the product side. So, in order to balance the reaction, NaCl on the reactant side is multiplied by 2. Thus, the balanced chemical equation is:

BaCl_2(aq) + Na_2SO_4(aq) \rightarrow BaSO_4(s) + 2NaCl(aq)

Hence, the precipitate that will form from the reaction of barium chloride dihydrate with sodium sulfate decahydrate is barium sulfate, BaSO_4.

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Answer:

B

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What determines the amount of chemical energy a substance has?
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6 0
3 years ago
Calculate the amount of energy required to melt 500 g of ice at 0oc. (δhfus=5.96 kj/mole; δhfus is the energy required to melt i
marta [7]
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</span>ΔH = 5.96 kJ/mol * 1 mol/18 g * 500 g
<em>ΔH = 165.56 kJ</em><span>
</span>
3 0
3 years ago
The melting point of aluminum is 660ºC. At what temperature will aluminum melt if you have 5 grams? 10 grams? Explain your answe
valkas [14]

Answer:

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5 0
3 years ago
A sample of a chromium-containing alloy weighing 3.450 g was dissolved in acid, and all the chromium in the sample was oxidized
Zina [86]

Answer:

H_2O + 2CrO_4^2- + 3SO_3^2- -> 3SO_3^2- + 2CrO_2^- + 2OH^-

Explanation:

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Oxidation half reaction

2OH^- + SO_3^2- -> SO_4^2- + H_2O + 2e

Balanced overall equation

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5 0
3 years ago
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