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Liono4ka [1.6K]
2 years ago
14

A using the strategy to determine the area of the large rectangle

Mathematics
1 answer:
Over [174]2 years ago
4 0

The area of the large rectangle by using the strategy is; 168cm².

<h3>What is the area of tge large rectangle?</h3>

The area of the rectangle can be determined by multiplying the length and width of the rectangle as follows;

Area = Length × width

Area = (10cm + 4cm) × (10cm × 2cm)

Area = (100+20+40+8)cm²

Area = 168 cm².

The strategy used above entails that the two binomials used to represent the length and width of the rectangle are multiplied according to binomial multiplication.

The strategy is that each term of the first binomials is used to multiply the terms in the second polynomial and the aggregate result of the multiplications is determined.

Read more on binomial multiplication;

brainly.com/question/24255913

#SPJ1

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<h3>Answers</h3>
  • 1a. Graph is decreasing on the interval 3 < x < 13.
  • 1b. Graph is increasing on two separate intervals: 0 < x < 3 \text{ and } 13 < x < 18
  • 2. Min value = 0.75, Max value = 3
  • 3. Domain = 0 \le x \le 18, Range = 0.75 \le y \le 3

=======================================================

Explanations:

  • 1a. The graph decreases whenever the curve goes downhill as you read from left to right. This is from x = 3 to x = 13. So the decreasing interval is 3 < x < 13See figure 1 below.
  • 1b. The graph increases when the graph goes uphill. This happens two separate times. First from x = 0 to x = 3. Then the second portion is from x = 13 to x = 18. Refer to figure 1.
  • 2. The min value is the smallest y value possible. This is y = 0.25 as shown in figure 2. This is where the lowest point on the so called "roller coaster" occurs. The max value is y = 3 which is where the highest point is located.
  • 3. The domain is the set of all allowed x values. This is from x = 0 to x = 18, including both endpoints. So we say the domain is 0 \le x \le 18. The range is a similar story but for the y values. The range is 0.75 \le y \le 3, which has its endpoints match up perfectly with the min and max found earlier.

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