Using the normal distribution, there is a 0.2148 = 21.48% probability that the sum of the 40 values is less than 7,100.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
- By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation
.
For this problem, these parameters are given as follows:

A sum of 7100 is equivalent to a sample mean of 7100/40 = 177.5, which means that the probability is the <u>p-value of Z when X = 177.5</u>, hence:

By the Central Limit Theorem:


Z = -0.79
Z = -0.79 has a p-value of 0.2148.
There is a 0.2148 = 21.48% probability that the sum of the 40 values is less than 7,100.
More can be learned about the normal distribution at brainly.com/question/28135235
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