Polynomials 4x^3 - X^2 + 12x-3=0

Mathematics

1 answer:

Dennis_Churaev [7]3 years ago

8 0

Answer:

1/4

Step-by-step explanation:

see steps below

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Y= -27(x+4)³+1 the real zero(s) is (are)

rjkz [21]

$\bf y=-27(x+4)^3+1\implies 0=-27(x+4)^3+1
\\\\\\
-1=-27(x+4)^3\implies \cfrac{-1}{-27}=(x+4)^3\implies \cfrac{1}{27}=(x+4)^3
\\\\\\
\sqrt[3]{\cfrac{1}{27}}=x+4\implies \cfrac{\sqrt[3]{1}}{\sqrt[3]{27}}=x+4\implies \cfrac{1}{3}=x+4\implies \cfrac{1}{3}-4=x
\\\\\\
-\cfrac{11}{3}=x$