Answer:
The linear momentum is zero
Explanation:
Because
When a rigid body is rotating about a fixed axis passing through point O, the body’s linear momentum given as L = mvG
But VG= 0 so
Linear momentum is zero
The compound is (Sulphuric Acid) H2SO4. On reacting with (Sodium Hydroxide) NaOH, it gives (2 Water Molecules/Colored) 2H2O and (1 Sodium Sulfate Molecule/Salt) Na2SO4
H2SO4 + NaOH —> 2H2O (aq.) + Na2SO4 (salt)
The resulted salt/compound (Na2SO4) when reacting with Methyl Orange (MO) is called ”Removal of methyl orange dye and Na2SO4 salt from synthetic wastewater using reverse osmosis (RO)”
The efficiency of reverse osmosis (RO) membranes used for treatment of colored water effluents can be affected by the presence of both salt and dyes.
Concentration polarization of each of the dye and the salt and the possibility of a dynamic membrane formed by the concentrated dye can affect the performance of the RO membrane.
The objective of the current work was to study the effect of varying the Na2SO4 salt and methyl orange (MO) dye concentrations on the performance of a spiral wound polyamide membrane.
The work also involved the development of a theoretical model based on the solution diffusion (SD) mass transport theory that takes into consideration a pressure dependent dynamic membrane resistance as well as both salt and dye concentration polarizations.
Control tests were performed using distilled water, dye/water and salt/water feeds to determine the parameters for the model.
The experimental results showed that increasing the dye concentration from 500 to 1000 ppm resulted in a decrease in the salt rejection at all of the operating pressures and for both feed salt concentrations of 5000 and 10,000 ppm.
Increasing the salt concentration from 5000 to 10,000 ppm resulted in a slight decrease in the percent dye removal. The model’s results agreed well with these general trends.
(a) The potential on the surface of a charged sphere of radius R is equal to
where
is the Coulomb's constant,
is the charge on the sphere's surface.
For the generator mentioned in the problem, the charge is
, while the radius is
. Using these values in the formula, we can calculate the potential at the surface:
(b) The potential generated by the sphere at a certain distance r from the centre of the sphere is given by
the problem asks at which distance
. Substituting in the previous formula we can find the value of r:
(c) An oxygen atom with 3 missing electrons has a positive charge of +3e, with e being the elementary charge.
The electric potential energy of a charged particle located at some point with voltage V is
where q is the charge of the particle, which is in our case
. So we can calculate the energy of the oxygen atom at the distance found in part b, which corresponds to
and a voltage of
: