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3 years ago

Please help I’ll give brainliest

Physics

1 answer:

In-s [12.5K]3 years ago

4 0

Answer:

2nd option

Explanation:

Static electricity the charges are at rest and they are accumulating on the surface of the insulator.

Current electricity the electrons are moving inside the conductor.

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A pitcher throws a curveball that reaches the catcher in 0.61 s. The ball curves because it is spinning at an average angular ve

sashaice [31]

Answer:

22.36 rad

Explanation:

Applying,

ω = θ/t.............. Equation 1

Where ω = angular velocity, θ = angular displacement of the baseball, t = time

make θ the subject of the equation

θ = ωt............... Equation 2

From the question,

Given: ω = 350 rev/min = 350(0.10472) = 36.652 rad/s, t = 0.61 s

Substitute these values into equation 1

θ = 0.61(36.652)

θ = 22.36 rad

Hence the angular displacement of the baseball is 22.36 rad

4 0

3 years ago

20pts<br> Physics wave. <br> Plz answer with explanation there are total 4 question

diamong [38]

Answer:

where are the questions?

8 0

3 years ago

If the plane is flying in a horizontal path at an altitude of 98.0 m above the ground and with a speed of 73.0 m/s, at what hori

snow_lady [41]

Explanation:

The given data is as follows.

height (h) = 98.0 m, speed (v) = 73.0 m/s,

Formula of height in vertical direction is as follows.

h = $\frac{gt^{2}}{2}$ ,

or, t = $\sqrt{\frac{2h}{g}}$

Now, formula for the required distance (d) is as follows.

d = vt

= $v \sqrt{\frac{2h}{g}}$

= $73.0 m/s \sqrt{\frac{2 \times 98.0 m}{9.8 m/s^{2}}}$

= 326.5 m

Thus, we can conclude that 326.5 m is the horizontal distance from the target from where should the pilot release the canister.

8 0

3 years ago

Which letter on the diagram below represents the retina of the eye? A) A B) B C) C D) D

Lorico [155]

Answer:

THE ANSWER IS OPTION C.

4 0

4 years ago

Read 2 more answers

In an old-fashioned amusement park ride, passengers stand inside a 4.9-m-diameter hollow steel cylinder with their backs against

Viefleur [7K]

Answer:

24.07415 rpm

Explanation:

$\mu$ = Coefficient of friction = 0.63

v = Velocity

d = Diameter = 4.9 m

r = Radius = $\frac{d}{2}=\frac{4.9}{2}=2.45\ m$

m = Mass

g = Acceleration due to gravity = 9.81 m/s²

Here the frictional force balances the rider's weight

$f=\mu F_n$

The centripetal force balances the weight of the person

$\mu m\frac{v^2}{r}=mg\\\Rightarrow \mu \frac{v^2}{r}=g\\\Rightarrow v=\sqrt{\frac{gr}{\mu}}\\\Rightarrow v=\sqrt{\frac{9.81\times 2.45}{0.63}}\\\Rightarrow v=6.17656\ m/s$

Velocity is given by

$v=\omega r\\\Rightarrow \omega=\frac{v}{r}\\\Rightarrow \omega=\frac{6.17656}{2.45}\\\Rightarrow \omega=2.52104\ rad/s$

Converting to rpm

$2.52104\times \frac{60}{2\pi}=24.07415\ rpm$

The minimum angular speed for which the ride is safe is 24.07415 rpm

4 0

3 years ago