All categories

3 years ago

Please help I’ll give brainliest

Physics

1 answer:

In-s [12.5K]3 years ago

4 0

Answer:

2nd option

Explanation:

Static electricity the charges are at rest and they are accumulating on the surface of the insulator.

Current electricity the electrons are moving inside the conductor.

You might be interested in

A machine has an efficiency of 80%. How much work must be done on the machine so to make it do 50,000 J of output work?

Tamiku [17]

Work formula is Work=N∙M or Joule (J)

So you have the following given:

50 000 is the output work

.8 is the efficiency

if you input the given = 50000 = .8*J

To get the answer just divide 50000 by .8 to get the answer.

62,500 J is the amount of work to be done.

8 0

3 years ago

Read 2 more answers

Which of the following group 7A elements is the most reactive?

nevsk [136]

Among the elements in group 7A, the most reactive would be Fluorine. Fluorine is a major component of toothpaste, what we use to brush and clean our teeth with. It is so reactive that it cannot be contained in glass.

8 0

4 years ago

Something that allows electrons to flow easily through it is called

SCORPION-xisa [38]

A closed path through which electrons flow. conductor. A material that allows electrons to move easily through it. current.

4 0

4 years ago

Read 2 more answers

During your summer internship for an aerospace company, you are asked to design a small research rocket. The rocket is to be lau

Thepotemich [5.8K]

Answer:

$T=6.75s$

Explanation:

We must separate the motion into two parts, the first when the rocket's engines is on and the second when the rocket's engines is off. So, we need to know the height ( $h_1$ ) that the rocket reaches while its engine is on and we need to know the distance ( $h_2$ ) that it travels while its engine is off.

For solving this we use the kinematic equations:

In the first part we have:

$h_1=v_0T+\frac{1}{2}aT^2\\h_1=0*T+\frac{1}{2}(16\frac{m}{s^2})T^2\\h_1=8\frac{m}{s^2}T^2\\$

and the final speed is:

$v_f=v_0+aT\\v_f=0+16\frac{m}{s^2}T\\v_f=16\frac{m}{s^2}T$

In the second part, the final speed of the first part it will be the initial speed, and the final speed is zero, since gravity slows it down the rocket.

So, we have:

$v_f^2=v_0^2+2gh_2\\2gh_2=v_f^2-v_0^2\\h_2=\frac{v_f^2-v_0^2}{2g}\\h_2=\frac{0^2-(16\frac{m}{s^2}T)^2}{2(-9.8\frac{m}{s^2})}\\h_2=\frac{-256\frac{m^2}{s^4}T^2}{-19.6\frac{m}{s^2}}\\h_2=13.06\frac{m}{s^2}T^2$

The sum of these heights will give us the total height, which is known:

$h=h_1+h_2\\960m=8\frac{m}{s^2}T^2+13.06\frac{m}{s^2}T^2\\960m=21.06\frac{m}{s^2}T^2\\T^2=\frac{960m}{21.06\frac{m}{s^2}}\\T^2=45.58s^2\\T=\sqrt{45.58s^2}\\T=6.75s$

This is the time that its needed in order for the rocket to reach the required altitude.

5 0

3 years ago

In the circuit diagram, what does the line segment with two circles at the end represent?

iragen [17]

I think it means a closed circut

5 0

4 years ago

Read 2 more answers