Answer:
22.36 rad
Explanation:
Applying,
ω = θ/t.............. Equation 1
Where ω = angular velocity, θ = angular displacement of the baseball, t = time
make θ the subject of the equation
θ = ωt............... Equation 2
From the question,
Given: ω = 350 rev/min = 350(0.10472) = 36.652 rad/s, t = 0.61 s
Substitute these values into equation 1
θ = 0.61(36.652)
θ = 22.36 rad
Hence the angular displacement of the baseball is 22.36 rad
Explanation:
The given data is as follows.
height (h) = 98.0 m, speed (v) = 73.0 m/s,
Formula of height in vertical direction is as follows.
h =
,
or, t =
Now, formula for the required distance (d) is as follows.
d = vt
=
=
= 326.5 m
Thus, we can conclude that 326.5 m is the horizontal distance from the target from where should the pilot release the canister.
Answer:
24.07415 rpm
Explanation:
= Coefficient of friction = 0.63
v = Velocity
d = Diameter = 4.9 m
r = Radius = 
m = Mass
g = Acceleration due to gravity = 9.81 m/s²
Here the frictional force balances the rider's weight

The centripetal force balances the weight of the person

Velocity is given by

Converting to rpm

The minimum angular speed for which the ride is safe is 24.07415 rpm